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alex41 [277]
3 years ago
7

Before posting a picture online, make sure to

Computers and Technology
1 answer:
chubhunter [2.5K]3 years ago
8 0
You have to make sure that the site is safe to post to avoid phishing. There are some options available in social media that can help you customize the settings of your viewers. It can give you more control to choose whether you wanted it to be seen in public, by friends or just yourself.  
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How many invalid code sequences can we have in 5b/6b encoding?
mart [117]
<span>In the process of 5B/6B encoding, it is possible to have the following two kinds of data sequences: 1. 25=32 data sequences 2. 26=64 data sequences Therefore, this can left us with some unused code sequences that are 32 in number (=26 – 25). On the other hand, in the encoding process of 3B/4B, it is possible to another set of data sequences as follows: 1. 23=8 data sequences 2. 24=16 data sequences This type of encoding also leaves us with some unused code sequences that are 8 in number (=23-24). 2. </span>
6 0
3 years ago
It's important to understand that even information systems that do not use computers
Delvig [45]

Answer:

yes I am not sure if you have any questions or concerns please visit the plug-in settings to determine how attachments are handled the situation in the measurements of the season my dear friend I am not sure if you can send you a great day to day basis of

6 0
3 years ago
The (X , y) coordinates of a certain object as a function of time' are given by Write a program to determine the time at which t
ra1l [238]

Answer:

t = [0:0.01:4];

x = 5*t - 10;

y = 25442 - 120*t + 144;

d = x.^2 + y.^2;

min = 1e+14;

for k = 1:length(t)

if d(k) < min

min = da(k);

tmin = t(k);

end

end

disp('The minimum distance is: ')

disp(sqrt(min))

disp('and it occurs at t = ')

disp(tmin)Output:

>> withLoop

The minimum distance is:

2.5106e+04

and it occurs at t =

4

Explanation:

4 0
3 years ago
Complete the method, longestWord(), below that takes in an array of Strings and returns the longest String in the array. Note: y
beks73 [17]

Answer:

I am writing a JAVA program.

public class StringMethod {

public static String longestWord(String []words) { //method that takes an array  "word" of strings and returns the longest string in the array word

    int pos = 0; // contains index of the longest word of array words

    int longest = words[0].length(); //initially holds the length of the 1st element of words array

    for(int i=1; i< words.length; i++) { // iterates through each word of the array until the end of array

        if(words[i].length() > longest) { // if the length of word at i-th index of words[] is greater than the length of the word that is contained in longest variable

            pos = i; // assigns the index of the longest array element to pos

            longest = words[i].length();    } } //assigns the word in words[] array with the longest length to longest variable

   return words[pos]; } // returns the longest string in the array    

public static void main(String[] args) { //start of main() function body

String[] animals = {"cat", "horse", "elephant", "bird"}; //creates a String type array named animals which has 4 elements/words

   String longest_word= longestWord(animals); //calls longestWord method to find the longest string in the array animals and assign that longest string to longest_word.

  System.out.println(longest_word); }} //displays the longest word in output

Explanation:

Suppose we have the array of these elements: "cat", "horse", "elephant", "bird" These are four words in the array. Now lets see how the method longestWord() works:

int pos = 0; This variable is initialized to 0.

int longest = words[0].length();

longest holds the length of element at 0th index of words[] array. length() method is used to return the length of the first element words[0] array.

As the first element of array is "cat" so length of cat is 3. Hence longest = 3

for(int i=1; i< words.length; i++)

The loop has a variable i which is initialized to 1. The loop checks if the value of i is less than length of words[] array. The length of words array is 4 as there are 4 elements i.e. cat, horse, elephant and bird in this array. So the condition evaluates to true because i<words.length i.e. 1<4. The body of the loop will execute now. The body of loop contains an if condition if(words[i].length() > longest) which checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=1 so word[i] is word[1] which is the second element of words[] array. The second element is horse.

words[i].length()  means the length of i-th element of words[] array. So this means words[1].length() i.e. the length of element of words[] at 1st index. The length of horse is 5. So the statement if(words[i].length() > longest) is true because longest=3 and words[1].length() = 5 and 5>3. So the statements of if condition will execute now.

pos = i; this variable pos is used to hold the index position of the longest element in array. So pos = 1 as longest element computed so far is "horse".

longest = words[i].length(); This statement then assigns the length of horse to longest. So now the value of longest = 5

At second iteration i is now 2.  Loop condition evaluates to true because i<words.length i.e. 2<4. If condition is also true as i=2 so word[i] is word[2] which is elephant.

words[i].length() now means words[2].length() i.e. the length of element of words[] at 2nd index. The length of elephant is 8. So the statement if(words[i].length() > longest) is true because longest=5 and words[2].length() = 8 and 8>5. So the statements of if condition will execute now.

pos = i; now becomes pos = 2 as longest element computed so far is "elephant".

longest = words[i].length();  This statement then assigns the length of horse to longest. So now the value of longest = 8

At third iteration i is now 3.  The loop again checks if the value of i is less than length of words[] array.The condition evaluates to true because i<words.length i.e. 3<4. The body of the loop will execute now.  if(words[i].length() > longest) checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=3 so word[i] is word[3] which is the fourth element of words[] array. The fourth element is bird.

words[i].length() now means words[3].length() i.e. the length of element of words[] at 3rd index. The length of bird is 4. So the statement if(words[i].length() > longest) is false because longest=8 and words[2].length() = 4 and 4<8. So the statements of if condition will not execute now.

At fourth iteration i is now 4.  The loop again checks if the value of i is less than length of words[] array.The condition evaluates to false because i==words.length i.e. 4=4. So the loop breaks.

 return words[pos]; statement returns the index position of longest word in words[] array. pos = 2 So the array element at 2nd index is basically the third element of array words[] i.e. elephant. So the longest string in the array is elephant.

8 0
3 years ago
write a pseducode that will ask the user to enter the amount of a purchase. The program should then compute that state and provi
stira [4]

The pseudocode of the program is simply a prototype of the actual program

<h3>How to write the pseudocode?</h3>

The pseudocode that does the requirements in the question is as follows:

  • Start
  • Get Input for amount of purchase
  • Compute the state tax: sales tax = sales tax percentage * amount
  • Compute the provisional sales tax: provisional sales tax = provisional sales tax percentage * amount
  • Print the taxes

Read more about pseudocode at:

brainly.com/question/24735155

#SPJ1

7 0
2 years ago
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