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3 years ago

Before posting a picture online, make sure to

1 answer:

8 0

You have to make sure that the site is safe to post to avoid phishing. There are some options available in social media that can help you customize the settings of your viewers. It can give you more control to choose whether you wanted it to be seen in public, by friends or just yourself.

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The operations planning practice of inputting sales forecasts into computer software that accurately predicts the amount and tim

netineya [11]

Answer:

"Materials requirement planning" is the correct answer for the above question.

Explanation:

The "Materials requirement planning" is a software system that is used to hold the record of the raw materials.
It is used to tell about the material which is present in the stocks. It also used to schedule the delivery.
This software is used to enhance the productivity of the company.
The above question asked about the software which is needed to keep the record of the raw material. This software is known as "Materials requirement planning".

3 0

3 years ago

2.1 Changes in which factors could cause aggregate demand to shift from AD to AD1? What could happen to the unemployment rate? W

katrin [286]

Answer:

There are many factors that cause aggregate demand to shift from AD to AD1. The unemployment rate will fall and inflation will increase.

Explanation:

A Shift in aggregate demand from AD to AD1 means there has been a fall in demand. Various factors that cause demand to decrease are:

Increase in price of a good itself
Increase in the price of complimentary goods-This will lead to a fall in demand. Like ink and pen are complementary goods. if the Price of ink increases then demand for pen will decrease.
A Decrease in the price of substitute goods-Like tea and coffee.
Expectation regarding future fall in price

So due to the decrease in demand finally the unemployment will increase and with that, the inflation rate will increase making things dearer.

3 0

3 years ago

A low concentration of market power has positive affects. A low concentration of market share has which of the following effects

lisov135 [29]

A or b i think hope it helps good luck and i hope it helps

6 0

3 years ago

To locate all locations in a document with the word "employer" and replace it with "company," you should use the _____ function.

grandymaker [24]

That should be the replace function which performs word replacements in documents.

6 0

3 years ago

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

2 years ago