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3 years ago

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In destroit at 10 am,the temperature was -6 degrees.By 2 pm,it had increased 20 degrees.what was the temperature at 11 am? (hint

:draw a number line).
A)14 degrees.
B)-26 degrees.
C)-14 degrees.
D)26 degrees.

1 answer:

MAVERICK [17]3 years ago

6 0

Answer:

A

Step-by-step explanation:

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myrzilka [38]

Answer:

As given whole numbers from 10 - 12 are paired with their factors.

factor of ,10=1,2,5,10 → (10,1),(10,2),(10,5)(10,10)

factor of 11=1, 11 → (11,1),(11,11)

factor of 12=1,2,3,4,6,12→ (12,1),(12,2),(12,3),(12,4),(12,6),(12,12)

As we know for an ordered pair to be function Every element in the domain must have a unique image, i.e it can't have more than one image.

→ As element 10, have four images,which are 1,2,5,10 so it can,t be a function.

Similarly element 11 have two images 1,11 so it can't be a function.

Element 12 have six images 1,2,3,4,6,12, so it also can't be written as function.

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3 years ago

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Answer:

B. 6-3

Step-by-step explanation:

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Ali graphs the function f(x) = -(x + 2)2 - 1 as shown.

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Step-by-step explanation:

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A market research team thinks that their new ad campaign is better than their old one. They used to be able to sell to 50% of th

andreev551 [17]

Answer:

a. The test statistic is 2 and we conclude that the new ad campaign is not signficantly better.

Step-by-step explanation:

They used to be able to sell to 50% of those who saw their ads. Test if the new campaign is better.

At the null hypothesis, we test is it is the same, that is, the proportion is the same.

$H_0: p = 0.5$

At the alternate hypothesis, we test if it is significantly better, that is, the proportion is above 50%.

$H_1: p > 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5$

They take a random sample of 100 potential buyers and find that they convinced 60 of these people to buy their product.

This means that $n = 100, X = \frac{60}{100} = 0.6$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.6 - 0.5}{\frac{0.5}{\sqrt{100}}}$

$z = 2$

The test statistic is 2.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion above 0.6, which is 1 subtracted the by p-value of z = 2.

Looking at the z-table, z = 2 has a p-value of 0.9772.

1 - 0.9772 = 0.0228.

The p-value of the test is 0.0228 > 0.01, which means that we cannot conclude that the new ad campaign is signficantly better, so the correct answer is given by option A.

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3 years ago