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Shalnov [3]
3 years ago
6

Simplify i^38 1) i 2) -1 3) -i 4) 1

Mathematics
2 answers:
alexdok [17]3 years ago
7 0
The awnser is supposed to be -1
Nataly_w [17]3 years ago
5 0

the answer is number 2.

- 1

You might be interested in
Hey can you please help me posted picture of question :)
otez555 [7]
Answer:
The solutions are -3 and -6

Explanation:
First we would need to put the equation in standard form which is:
ax² + bx + c = 0
This can be done as follows:
x² + 18 = -9x
x² + 9x + 18 = 0
By comparison, we would find that:
a = 1
b = 9
c = 18

Now, to get the roots, we would use the quadratic formula shown in the attached image.

By substitution, we would find that:
either x = \frac{-9+ \sqrt{(9)^2-4(1)(18)} }{2(1)} = -3

or x = \frac{-9- \sqrt{(9)^2-4(1)(18)} }{2(1)} = -6

Hope this helps :)

4 0
3 years ago
Read 2 more answers
What is the quotient?
Sergio039 [100]

Answer: FIRST OPTION

Step-by-step explanation:

According the quotient of powers property, when you have the division of two powers with the same base, then you must subtract the exponents.

Therefore, keeping the property above on mind, you have that the quotient is the shown below:

\frac{(-7)^2}{(-7)^{-1}}=(-7)^{(2-(-1))}=(-7)^{(2+1)}=(-7)^3=-343

6 0
3 years ago
Help asap please ----------------
melomori [17]

Answer:

-1 Not in domain

0 In domain

1 In domain

Step-by-step explanation:

The domain for the square root function is all positive numbers including (0). The domain is the set of real numbers which when substituted into the function will produce a real result. While one can substitute a negative number into the square root function and get a result, however, the result will be imaginary. Therefore, the domain for the square root function is all positive numbers. It can simply be expressed with the following inequality:

x\geq0

Therefore, one can state the following about the given numbers. Evaluate if the number is greater than or equal to zero, if it is, then it is a part of the domain;

-1 => less than zero; Not in domain

0 => equal to zero; <em> </em>In domain

1  => greater than zero: In domain

4 0
3 years ago
John wants to make a 100 ml of 6% alcohol solution mixing a quantity of a 3% alcohol solution with an 8% alcohol solution. What
mart [117]

Answer:

-50 ml of 3% alcohol solution and 150 ml of 8% alcohol solution

Step-by-step explanation:

For us to solve this type of mixture problem, we must represent the problem in equations. This will be possible by interpreting the question.

Let the original volume of the first alcohol solution be represented with x.

The quantity of the first alcohol solution needed for the mixture is 3% of x

                   ⇒ \frac{3}{100} * x

                       = 0.03x

Let the original volume of the second alcohol solution be represented with y.

The quantity of the second alcohol solution needed for the mixture is 5% of y

                   ⇒ \frac{5}{100} * y

                       = 0.05y

The final mixture of alcohol solution is 6% of 100 ml

                 ⇒ \frac{6}{100} * 100 ml

                       = 6 ml

Sum of values of two alcohol solutions = Value of the final mixture

                     0.03x + 0.05y = 6 ml               ..........(1)

Sum of original quantity of each alcohol solution = Original volume of the of mixture

                     x + y = 100 ml                          ..........(2)      

For easy interpretation, I will be setting up a table to capture all information given in the question.

Component                       Unit Value      Quantity(ml)       Value

3% of Alcohol solution        0.03                 x                     0.03x

8% of Alcohol solution        0.08                 y                     0.08y

Mixture of 100ml of 6%        0.06               100                       6    

                                                                x + y = 100       0.03x + 0.08y =6

Looking at the equations we derived, we have two unknowns in two equations which is a simultaneous equation.

                                0.03x + 0.05y = 6 ml               ..........(1)

                                x + y = 100 ml                           ..........(2)    

Using substitution method to solve the simultaneous equation.

Making x the subject of formula from equation (2), we have,

                                x  = 100 - y                                 ..........(3)

Substituting  x  = 100 - y from equation (3) into equation (1)

                               0.03(100 - y) + 0.05y = 6  

                               3 - 0.03y + 0.05y = 6  

Rearranging the equation,            

                               0.05y - 0.03y = 6 - 3

                               0.02y = 3

                               y = \frac{3}{0.02}

                               y = 150 ml

Substituting y = 150 ml into equation (3) to get x

                              x  = 100 - 150 ml

                              x = - 50 ml

The quantity of the first alcohol solution needed for the mixture for 3% is - 50 ml

The quantity of the second alcohol solution needed for the mixture for 5% is 150 ml

This solution means 50 ml of the first alcohol solution must be removed from the mixture with 150 ml of the second alcohol solution to get a final mixture of 100 ml of 6% alcohol solution.

3 0
3 years ago
The St. Croix junior hockey
Alja [10]

Answer:

14

Step-by-step explanation:

56 divided by 4 is 14

7 0
3 years ago
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