Given t = time and h = height
![h(t) = - 16(t - 1)^{2} + 16](https://tex.z-dn.net/?f=h%28t%29%20%3D%20%20-%2016%28t%20-%201%29%5E%7B2%7D%20%20%2B%2016)
From the equation.
![y = a(x - h)^{2} + k](https://tex.z-dn.net/?f=y%20%3D%20a%28x%20-%20h%29%5E%7B2%7D%20%20%2B%20k)
h is the axis od symmetry
(h, k) is the vertex.
In the equation, h is 1 and k is 16.
So the maximum value is 16 at t = 1.
The ball reaches maximum at 16 and it takes t = 1 to reach the maximum point.
It should be B or C
Step-by-step explanation:
Answer:
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Step-by-step explanation:
least of 3 consecutive integers is a, and the greatest is z
if a is the least one
we know that integers differ by value of 1.
example -2, -1, 0, 1,2
they all differ by
then next consecutive integer will be a+1
third integer will be second integer +1 = a+1 + 1 = a+2
Thus, 3 consecutive integer
a , a+1, a+2
but given that greatest is z
thus, a+2 is greatest and hence
a+2 = z
we have to find value of a + 2z/ 2 in terms of a
a + 2z/ 2 = a + 2(a+2)/2 = (a+ 2a +4)/2 = (3a+4)/2.
The value of a + 2z/ 2 in terms of a is (3a+4)/2
F (x) = 5(4) ^x Is the right answer