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vova2212 [387]
3 years ago
9

Your bank account has a balance of −$12. You deposit $60. What is your new balance?

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0

Answer:

Your balance will be 48

Step-by-step explanation:

If you have -12 add 60 that will equal 48

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Algebra 2 question need help.​
MrMuchimi

Answer: Choice C

h(x) = -x^4 + 2x^3 + 3x^2 + 4x + 5

===========================================

Explanation:

When reflecting the function f(x) over the y axis, we replace every x with -x and simplify like so

f(x) = -x^4 - 2x^3 + 3x^2 - 4x + 5

f(-x) = -(-x)^4 - 2(-x)^3 + 3(-x)^2 - 4(-x) + 5

f(-x) = -x^4 + 2x^3 + 3x^2 + 4x + 5

h(x) = -x^4 + 2x^3 + 3x^2 + 4x + 5

Note the sign changes that occur for the terms that have odd exponents (the terms -2x^3 and -4x become +2x^3 and +4x); while the even exponent terms keep the same sign.

The reason why we replace every x with -x is because of the examples mentioned below

-----------

Examples:

The point (1,2) moves to (-1,2) after a y axis reflection

Similarly, (-5,7) moves to (5,7) after a y axis reflection.

As you can see, the y coordinate stays the same but the x coordinate flips in sign from negative to positive or vice versa. This is the direct reason for the replacement of every x with -x.

4 0
2 years ago
Subtract 3x^2+7x-4 from 8x^2-6x+2
solong [7]

Answer:

5x^2-13x+6

Step-by-step explanation:

(8x^2-6x+2)-(3x^2+7x-4)

8x^2-3x^2-6x-7x+2-(-4)

5x^2-13x+2+4

5x^2-13x+6

3 0
3 years ago
A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s
Bas_tet [7]

Answer:

Step-by-step explanation:

m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}

3 0
2 years ago
In the diagram AB is parallel to CD. What is the term for the line that intersects the two parallel lines?
yanalaym [24]
A transversal intersects two parallel lines, given that the lines are on the same plane. 
5 0
2 years ago
Read 2 more answers
Consider the trapezoid below.
Nuetrik [128]

Answer:

57cm²

Step-by-step explanation:

area for trapezoid=

b¹+b²=x

x÷2=v

v×h=z

h=height

b=base

14+5=19

19÷2=9.5

9.5×6=57

3 0
2 years ago
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