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GuDViN [60]
2 years ago
8

What is the equation of the line that passes through the point (-5,-4) and has a slope of -3/5

Mathematics
2 answers:
vagabundo [1.1K]2 years ago
8 0

Answer:

y= -3/5x - 7 (assuming slope-intercept form)

Step-by-step explanation:

First, we see the slope. The basic template for a slope-intercept question is

y=mx + b

So, we put in -3/5 as "m" in this case, as it is the slope to get y= -3/5x +b

To find b, we can just try out the point that the equation gave us.

-3/5 * -5 = 3

Then, to get to -4 from 3, we need to subtract 7.

Then, we get our whole slope-intercept equation. y=-3/5x - 7

kakasveta [241]2 years ago
6 0

Answer:

The equation is y = 3/5x - 1

Step-by-step explanation:

1. Construct an equation. We can use the slope-point formula to construct an equation from these (y - y₁ = slope * (x - x₁)). If you plug in these values, you'll get the equation y + 4 = -3/5(x +5).

2. Simplify. If you simplify, you'll get that y = 3/5x - 1 by isolating y.

Answer: The equation of the line is y = 3/5x - 1.

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Answer: Choice A) 8.742 * 10^7

=====================================

Work Shown:

(a * 10^b) \times (c * 10^d) = a*c*10^{b+d}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 2.82*3.1*10^{4+3}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 8.742*10^{7}\\\\

Extra info:

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