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goblinko [34]
3 years ago
9

A phone company charges a monthly rate of $60 and $0.10 per text sent . Tara sends 100 text messages this month . How much is he

r phone bill b, going to cost ?
Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
4 0

Answer:

Taras phone bill will be 70 doll hairs.

Step-by-step explanation:

100x.10=10

10+60

70

hope this helps!!!

Annette [7]3 years ago
4 0

Answer:

70 dollars

Step-by-step explanation:

0.10 times 100 is 10 dollars. 60 plus 10 equals 70 dollars a

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The equation of the line that is parallel to the line whose equation is 3x-2y=7 would be y = 3/2x + b, in which b can be any real number.

How are parallel straight lines related?

Parallel lines have the same slope since the slope is like a measure of steepness and since parallel lines are of the same steepness, thus, are of the same slope.

We have been given a parallel line with has equation

3x-2y=7

In order to solve this, the slope of the original line.

3x - 2y = 7

-2y = -3x + 7

y = 3/2x - 7/2

thus its slope is 3/2.

thus, the slope of the needed line is 3/2 too.

we know that any line that is parallel to that would have this slope.

So anything is written in the form:

y = 3/2x + b

The equation of the line that is parallel to the line whose equation is 3x-2y=7 would be y = 3/2x + b, in which b can be any real number.

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1 year ago
A number of two digits is increased by 54 when the digits are reversed. The ten digits is three times the unit digit. Find the n
bija089 [108]

Let <em>n</em> be the unknown number. We can write it as

<em>n</em> = 10<em>a</em> + <em>b</em>

with <em>a</em> and <em>b</em> integers between 1 and 9 (either with positive or negative sign).

Reversing the digits gives another number

<em>m</em> = 10<em>b</em> + <em>a</em>

The first number is increased by 54 when the digits are reversed, which means

<em>m</em> = <em>n</em> + 54   →   10<em>b</em> + <em>a</em> = 10<em>a</em> + <em>b</em> + 54   →   9<em>b</em> - 9<em>a</em> = 54   →   <em>b</em> - <em>a</em> = 6

The digit in the tens place of <em>n</em> is 3 times the digit in the ones place, so

<em>a</em> = 3<em>b</em>

Substitute this into the previous equation and solve for <em>b</em> :

<em>b</em> - <em>a</em> = <em>b</em> - 3<em>b</em> = -2<em>b</em> = 6   →   <em>b</em> = -3

Solve for <em>a</em> :

<em>a</em> = 3<em>b</em> = 3(-3) = -9

Then the original number is <em>n</em> = 10<em>a</em> + <em>b</em> = 10(-9) + (-3) = -93

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4 years ago
Use the Chain Rule to find the indicated partial derivatives. u = x2 + yz, x = pr cos(θ), y = pr sin(θ), z = p + r; (partial u)/
devlian [24]

u(x,y,z)=x^2+yz

\begin{cases}x(p,r,\theta)=pr\cos\theta\\y(p,r,\theta)=pr\sin\theta\\z(p,r,\theta)=p+r\end{cases}

At the point (p,r,\theta)=(2,2,0), we have

\begin{cases}x(2,2,0)=4\\y(2,2,0)=0\\z(2,2,0)=4\end{cases}

Denote by f_x:=\dfrac{\partial f}{\partial x} the partial derivative of a function f with respect to the variable x. We have

\begin{cases}u_x=2x\\u_y=z\\u_z=y\end{cases}

The Jacobian is

\begin{bmatrix}x_p&x_r&x_\theta\\y_p&y_r&y_\theta\\z_p&z_r&z_\theta\end{bmatrix}=\begin{bmatrix}r\cos\theta&p\cos\theta&-pr\sin\theta\\r\sin\theta&p\sin\theta&pr\cos\theta\\1&1&0\end{bmatrix}

By the chain rule,

u_p=u_xx_p+u_yy_p+u_zz_p=2xr\cos\theta+zr\sin\theta+y

u_p(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_p(2,2,0)=16}

u_r=u_xx_r+u_yy_r+u_zz_r=2xp\cos\theta+zp\sin\theta+y

u_r(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_r(2,2,0)=16}

u_\theta=u_xx_\theta+u_yy_\theta+u_zz_\theta=-2xpr\sin\theta+zpr\cos\theta

u_\theta(2,2,0)=-2\cdot4\cdot2\cdot2\sin0+4\cdot2\cdot2\cos0\implies\boxed{u_\theta(2,2,0)=16}

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3 years ago
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