The equation of a cirecle with radius r and center at (h,k) is
(x-h)^2+(y-k)^2=r^2
r=10
center=(-2,-4)
(x+2)^2+(y+4)^2=10^2
(x+2)^2+(y+4)^2=100
(x,y)
sub given points (or use TI) and see if you get a true statmeent
A is on it
answer is A
Answer:
Answer below
Step-by-step explanation:
4(x−1)
2
=10−2
4(x−1)
2
=8
(x−1)
2
=
4
8
(x−1)
2
=2
x −1=±√
2
x−1=√
2
x-1=-\sqrt{2}x−1=−√
2
x=√
2
+1
x=−√
2
+1
x=√
2
+1,−√
2
+1
Answer:
2/3
Step-by-step explanation:
We can use the slope formula
m = (y2-y1)/(x2-x1)
= (12-8)/(4 - -2)
(12-8)/(4+2)
4/6
2/3
Answer:
Steps for Constructing the Incenter of a Triangle
Step 1: Construct an angle bisector for one of the angles of the triangle. ... Step 2: Construct an angle bisector for another angle of the triangle. ... Step 3: Find the point where these two angle bisectors intersect.
Step-by-step explanation:
Probability between z = 0 and z = 3.01 is given by
P(0<z<3.01) = P(z<3.01) - P(z<0)
Reading from the z-table, we have
P(z<0) = 0.5
P(z<3.01) = 0.9987
Hence, P(0<z<3.01) = 0.9987 - 0.5 = 0.4987
