The answer would be A. Reflection over line a. Hope this helps, and good luck!
Answer:
c .Perfect square trinomials
d.Difference of perfect squares
Step-by-step explanation:
We have to find the special product formulas.
a.Perfect square monomials
It is of the form 
It is not a special product formulas.
b.Difference of terms
It is of the form

It is not a special product formulas.
c.Perfect square trinomials
It is of the form

It is a special product formulas.
d.Difference of perfect squares
It is of the form


Therefore, it is a special product formulas.
I. 3*2^0
II. 3*2^1
III 3*2^2
IV. 3*2^3
V. 3*2^4
VI. 3*2^5
The sum 3*(2^0+2^1+2^2+2^3+2^4+2^5)=3*(2^6-1)=3*(64-1)=3*63=189
D is the answer
Hi , you have to divide the numerator and the denominator , if you get a decimal you just have to move the period 2 spaces to the right.
For example
3/8 -0.375
0.375 - 37.5
A. 3^n 3^20
b.N^n N^20
c.12^n 12^9
d.237^n 237^4