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hodyreva [135]
3 years ago
12

Trevor has finished reading 55% of a book.

Mathematics
1 answer:
Sholpan [36]3 years ago
8 0
You would have to find 55 % of 400


\frac{x}{400} =  \frac{55}{100}
Find X
100x / 400 = 55
100x = 55 X 400
100x = 22000
x = 220

Trevor has read 220 pages.
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A mystery element has 18 protons. Which one of the following statements is true about the element?
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Step-by-step explanation:

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a twelve sided die with side labeled 1-12 will be rolled once. What is the probability of rolling a number less than 9?
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1 year ago
The cosine of 23° is equivalent to the sine of what angle
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Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

\cos(90^\circ-x)=\sin(x)

or

\sin(90^\circ-x)=\cos(x)

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

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