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3 years ago

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The probability that Ashley drives faster than the speed limit (event A) is 0.34, and the probability that he gets a speeding ti

cket (event B) is 0.22. The probability that he drives faster than the speed limit, given that he has gotten a speeding ticket, is 1. Are events A and B dependent or independent? A. dependent B. independent C. insufficient data D. depends on the other events in the sample space

2 answers:

mezya [45]3 years ago

7 0

Answer: Option 'A' is correct

Step-by-step explanation:

Since we have given that

A be the event that Ashley drives faster than the speed limit.

P(A)=0.34

B be the event that he gets a speeding ticket.

P(B)=0.22

Probability that he drives faster than the speed limit, given that he has gotten a speeding ticket i.e.

P(A|B)=1

but for A and B to be independent ,

P(A).P(B)= P(A and B)

0.34×0.22=0.0748

but,

$P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}\\\\1=\dfrac{P(A\cap B)}{0.22}\\\\0.22=P(A\cap B)$

So, P(A∩B) does not satisfy the condition.

Hence, A and B are not independent events.

Option 'A' is correct as they are dependent events.

Wittaler [7]3 years ago

4 0

The correct answer between all

the choices given is the first choice or letter A. I am hoping that this answer

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For stuff like this you have to simplify the equation and solve for x.

But since its multiple choice you can just plug in each answer until it makes the equation true.

So here are the equations with n substituted in:

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Now simplify:

8(8+1)+3=45 becomes 72+3 = 45

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Its easiest to start with the highest option given and then go down. Because 8 is already way to high you could skip doing the math for 7 and go straight to 5 and 6.

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30+3=45 becomes 33=45

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3 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

What are the solutions of 2x2 - 6x+5=0?

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4 years ago

Can someone find F(12).<br> i really have no idea...<br> Please and thank you?

posledela

Answer: 909.03

Step-by-step explanation:

We know that the equation is an exponential function, it can be written as y=ab^x

$100 &=a b^{6.5} \dots \mathrm{Equation \ 1} \\11 &= a b^{1} \\$

$\Rightarrow ab^1=11$

$\Rightarrow \frac{ab^1}{b}=\frac{11}{b};\quad \:b\ne \:0$

$\Rightarrow a=\frac{11}{b}$

a = 11/b, substitute it in equation 1

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$\Rightarrow 100=\left(\frac{11}{b}\right)b^{6.5}$

$\Rightarrow 100b=11b^\frac{11}{2}$

$\Rightarrow 11\sqrt{b^{11} } =100b$

$\Rightarrow \sqrt{b^{11} } =\frac{100}{11}}$

$\Rightarrow \sqrt{b^{11} } =\frac{100}{11}}$

$\Rightarrow {b^{11} } =\frac{10000}{121}}$

$\Rightarrow {b} =\frac{\sqrt[11]{10000 \cdot 11^9} }{11}$

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Equation: y = (7.36382)(1.49379)^x

Now plug in 12 for x:
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2 years ago