9−z9, minus, z when z = 8z=8z, equals, 8.

Please answer this correctly

Mila [183]

Answer:

50%

Step-by-step explanation:

not even = 2 nums

pnoteven = 2 ÷ 4 × 100

3 0

3 years ago

Read 2 more answers

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

irga5000 [103]

Answer:

The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

Step-by-step explanation:

Let $C = (h,k)$ the coordinates of the center of the circle, which must be transformed into $C'=(h', k')$ by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

$(x-h)^{2}+(y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) Center of the circle is translated 4 units to the right (+x direction):

$C''(x,y) = C(x, y) + U(x,y)$ (Eq. 1)

Where $U(x,y)$ is the translation vector, dimensionless.

If we know that $C(x, y) = (h,k)$ and $U(x,y) = (4, 0)$ , then:

$C''(x,y) = (h,k)+(4,0)$

$C''(x,y) =(h+4,k)$

2) Reflection over the x-axis:

$C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)]$ (Eq. 2)

Where $O(x,y)$ is the reflection point, dimensionless.

If we know that $O(x,y) = (h+4,0)$ and $C''(x,y) =(h+4,k)$ , the new point is:

$C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]$

$C'(x,y) = (h+4, 0)-(0,k)$

$C'(x,y) = (h+4, -k)$

And thus, $h' = h+4$ and $k' = -k$ . The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

4 0

3 years ago

How do I solve this geometry problem?????

arsen [322]

Take the equations and solve them. they should lead up to degrees. Then add those degrees together and subtract that answer by 360 degrees and that should be your answer.

Hope this helps

3 0

3 years ago

A patient ingests 5 grams of a certain drug which

IgorC [24]

Answer:

8 hours

Step-by-step explanation:

5 - 1 = 4 grams

10% of 5 = 0.5 grams per hour

4/0.5 = 8 hours

8 0

3 years ago

A line passes through the point (8,-9) and has a slope of -5/2. Write an equation in slope intercept form for this line.

noname [10]

Answer:

y = - $\frac{5}{2}$ x + 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - $\frac{5}{2}$ , then

y = - $\frac{5}{2}$ x + c ← is the partial equation

To find c substitute (8, - 9) into the partial equation

- 9 = - 20 + c ⇒ c = - 9 + 20 = 11

y = - $\frac{5}{2}$ x + 11 ← equation of line

4 0

3 years ago