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asambeis [7]
3 years ago
12

What is the answer? To this question

Mathematics
1 answer:
Sauron [17]3 years ago
6 0
So first divide 420 by 3 which gets you 140 so now you need to divide that 140 by 20 which is 7 so the jeweler could make 7 necklaces which is B. If you have any questions just ask. Hope I helped you ❤️
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Find the equation of a line with each of the following characteristics.
Afina-wow [57]

Answer:

y=3x-1

Step-by-step explanation:

In parallel lines, the slope stays the same and the y-intercept changes. Hope this helps and I'm always here if you need me!

3 0
3 years ago
Jacob helps paint a square mural in his classroom. Then he helps paint a mural in the hallway whose length is 6 feet longer and
julia-pushkina [17]
Dimensions of the hallway mural:
L = x + 6,  W = x - 2. 
An expression is:
A ( hallway mural ) = ( x + 6 ) · ( x - 2 )
If x = 8 ft ( length of each side of the classroom ):
A ( h. m . ) = ( 8 + 6 ) · ( 8 - 2 ) =
= 14 · 6 = 84 ft²
The area of the hallway mural is 84 ft².
3 0
4 years ago
Read 2 more answers
Solve the equation 3= d+2<br> Will give brainliest be quick plz
Basile [38]

Answer:

d=1

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
!SUBSTITUTION METHOD!<br><br>6y - 5z = -8 <br>3z = -6 <br>4x - 3y - 2z= 21​
hichkok12 [17]

Answer:

<h2>x = 2 </h2><h2>y = - 3</h2><h2>z = - 2</h2>

Step-by-step explanation:

6y - 5z = -8 .......... Equation 1

3z = -6 ................... Equation 2

4x - 3y - 2z= 21...... Equation 3

<u>First solve for z in Equation 2</u>

That's

3z = - 6

Divide both sides by 3

<h3>z = - 2</h3>

Next substitute the value of z into Equation 1 in order to find y

We have

6y - 5(-2) = - 8

6y + 10 = - 8

6y = - 8 - 10

6y = - 18

Divide both sides by 6

<h3>y = - 3</h3>

Finally substitute the values of y and z into Equation 3 to find the value of x

That's

4x - 3(-3) - 2(-2) = 21

4x + 9 + 4 = 21

4x + 13 = 21

4x = 21 - 13

4x = 8

Divide both sides by 4

<h3>x = 2</h3>

So the solutions are

<h3>x = 2 </h3><h3>y = - 3</h3><h3>z = - 2</h3>

Hope this helps you

3 0
3 years ago
For each expression, select all equivalent expressions from the list.
ratelena [41]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's find the equivalent expressions ~

#1. PROBLEM

\qquad \tt \dashrightarrow \:11x - 4x + 10x

\qquad \tt \dashrightarrow \:21x - 4x

\qquad \tt \dashrightarrow \:17x

#2. PROBLEM

\qquad \tt \dashrightarrow \:2(1 + 8y)

\qquad \tt \dashrightarrow \:(2 \times 1) + (2 \times 8y)

\qquad \tt \dashrightarrow \:2 + 16y

8 0
2 years ago
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