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Y_Kistochka [10]
2 years ago
12

During a study that lasted 41 days, a flock of chickens was fed 50.43 kg of food. What was the average daily rate at which the f

lock was fed?
Mathematics
1 answer:
Eduardwww [97]2 years ago
7 0
1.23 kg of food per day
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Delia drives 220 km in 2 hours. Calculate her average speed in km/hrs.
alexira [117]
110 because avg speed is total distance over total time
8 0
3 years ago
The angle of elevation to the top of a skyscraper is measured to be 2° from a point on the ground 1 mile from the building. How
Nadusha1986 [10]

See picture below for a geometric view.


Let x = height of building


We use basic trigonometry to find x.


The tangent function = opposite side of right triangle OVER adjacent side of right triangle.


tan(2°) = x/1


Solve for x.


After multiplying both sides by 1 (here 1 represents 1 mile), we get

tan(2°) = x.


We now use the calculator to find x.


In fact, you can take it from here. Use your calculator.


3 0
3 years ago
What is the 56th term of the sequence below?<br> -29, -25, -21, -17, . . .
dimulka [17.4K]
The 56th term in the sequence is 195
6 0
3 years ago
Read 2 more answers
Iodine-125 has a half-life of about 60 days. How many milligrams of a 1000 mg sample will remain after 240 days?
Tomtit [17]

240 days is 4 times the half-life, which means that a sample of 1000 mg will decay to

\dfrac{1000}{2^4}=\dfrac{125}2=62.5\,\mathrm{mg}

after 240 days.

3 0
3 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
2 years ago
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