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2 years ago

If x is equal to 2 minus root 3 find the value of x minus one upon X whole cube

1 answer:

8 0

"2 minus root 3" => 2 - sqrt(3)

x does not appear here. That could cause a problem.

Unsure of what you mean by "x minus one upon X whole cube." Would you please go back to the original question and ensure that you have copied it down precisely. Without "x" in your equation, there's nothing to solve for.

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Help please! <br> Solve. 4/5x - 3 ¾ x = 2 ½

german

X= - 50/59
Hope this helped.

4 0

2 years ago

The two boxes shown are cuboids.

tensa zangetsu [6.8K]

Answer:

250 smaller cuboids

Step-by-step explanation:

Given

Small and Big cuboids

Required

Number of smaller cuboids in the big one

To do this, we calculate the volume of both cuboids.

$Volume = Length * Width * Height$

For the small cuboid

$V_1 = 10cm * 3cm * 4cm$

$V_1 = 120cm^3$

For the big cuboid

$V_2 = 50cm * 30cm * 20cm$

$V_2 = 30000cm^3$

The number of small in big is then calculated by diving the volumes

$Number = \frac{V_2}{V_1}$

$Number = \frac{30000cm^3}{120cm^3}$

$Number = \frac{30000}{120}$

$Number = 250$

Hence, there are 250 small cuboids in the large one

5 0

2 years ago

Solve the equation <br> (x/x+2) - (4/x-2) = 1

liubo4ka [24]

Answer:

<h2> $\bold{x=-\dfrac23}$ </h2>

Step-by-step explanation:

$\dfrac x{x+2}-\dfrac4{x-2}=1\qquad\qquad\qquad x\ne2\ \wedge\ x\ne-2\\\\\\ \dfrac {x(x-2)}{(x+2)(x-2)}-\dfrac{4(x+2)}{(x-2)(x+2)}=1\\\\\\ \dfrac {x^2-2x-4x-8}{x^2-4}=1\\\\ \\\dfrac {x^2-6x-8}{x^2-4}=1\quad\iff\quad x^2-6x-8=x^2-4\\\\x^2-6x-8=x^2-4\\\\-6x-8=-4\\\\-6x=4\\\\x=-\frac46\\\\x=-\frac23$

4 0

2 years ago

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Fofino [41]

The answer is m=250-25w

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2 years ago

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It's still remained un-touched. But will it hold for long?

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2 years ago