Please answer fast im in a hurry and im panicking. (5×1,000)+(9×1)+(2×1/10)+(6×1/1,000).

Alex Ar [27]

$Y= \frac{11}{2} x$

8 0

4 years ago

Paleomagnetic studies of Canadian volcanic rock known as the Carmacks Group have recently been completed. The studies revealed t

Naya [18.7K]

Answer:

a) 0.0228 = 2.28% probability of a northward displacement of less than 500 kilometers

b) 0.0808 = 8.08% probability of a northward displacement of less than 500 kilometers

c) 1200 kilometers, because in this case, the will be a higher probability of a northward displacement that is less than 500 kilometers.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Standard deviation of 500 kilometers

This means that $\sigma = 500$

a. Assuming the mean is 1500 kilometers, what is the probability of a northward displacement of less than 500 kilometers?

Mean of 1500 km means that $\mu = 500$

The probability is the pvalue of Z when X = 500. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{500 - 1500}{500}$

$Z = -2$

$Z = -2$ has a pvalue of 0.0228

0.0228 = 2.28% probability of a northward displacement of less than 500 kilometers.

b. Assuming the mean is 1200 kilometers, what is the probability of a northward displacement of less than 500 kilometers?

Now $\mu = 1200$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{500 - 1200}{500}$

$Z = -1.4$

$Z = -1.4$ has a pvalue of 0.0808

0.0808 = 8.08% probability of a northward displacement of less than 500 kilometers.

c. If, in fact, the northward displacement is less than 500 kilometers, which is the more plausible mean, 1200 or 1500 kilometers?

1200 kilometers, because in this case, the will be a higher probability of a northward displacement that is less than 500 kilometers.

3 0

2 years ago

Rashad has 24 jolly ranchers and 56 blow pops. what is the largest number of snack bags he could make?

mixas84 [53]

To find out the largest number of snack bags that Rashad could make, we need to find the GCF of 24 and 56

Because,

GCF of 24 and 56 is the largest possible number that divides 24 and 56 exactly without any remainder. The factors of 24 and 56 are 1, 2, 3, 4, 6, 8, 12, 24 and 1, 2, 4, 7, 8, 14, 28, 56 respectively.

There are 3 commonly used methods to find the GCF of 24 and 56 - long division, Euclidean algorithm, and prime factorization.

By Prime factorisation :

Prime factorization of 24 and 56 is (2 × 2 × 2 × 3) and (2 × 2 × 2 × 7) respectively.

As visible, 24 and 56 have common prime factors. Hence, the GCF of 24 and 56 is 2 × 2 × 2 = 8.

By Euclidean algorithm :

As per the Euclidean Algorithm, GCF(X, Y) = GCF(Y, X mod Y) where X > Y and mod is the modulo operator.

Here X = 56 and Y = 24

GCF(56, 24) = GCF(24, 56 mod 24) = GCF(24, 8)
GCF(24, 8) = GCF(8, 24 mod 8) = GCF(8, 0)
GCF(8, 0) = 8 (∵ GCF(X, 0) = |X|, where X ≠ 0)

Therefore, the value of GCF of 24 and 56 is 8.

By Long division :

GCF of 24 and 56 is the divisor that we get when the remainder becomes 0 after doing long division repeatedly.

Step 1: Divide 56 (larger number) by 24 (smaller number).
Step 2: Since the remainder ≠ 0, we will divide the divisor of step 1 (24) by the remainder (8).
Step 3: Repeat this process until the remainder = 0.

The corresponding divisor (8) is the GCF of 24 and 56.

Hence,

Hence,Rashad can make 8 snack bags

Learn more about GCF at : brainly.com/question/11444998

#SPJ4