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atroni [7]
4 years ago
15

Which expression represents the volume, in cubic units, of the composite figure?

Mathematics
2 answers:
malfutka [58]4 years ago
5 0
<span>1/3(8)(6)(6) + (8)(6)(4); the first answer choice would be correct. You would use the formula for the volume of this figure. Due to that, all you would have to do is substitute each number given on the figure into the formula and you will get the expression necessary for solving the volume.</span>
Lilit [14]4 years ago
3 0

the first answer choice is correct!!!!!!!!!!!!!!!!!!!!!! :D

1/3(8)(6)(6) + (8)(6)(4)

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For Part A, you need to input x=6 into the equation 8x + 8 = 56 to see if 6 is a solution of that equation. It'll be 8(6) + 8 = 56 -> 48 + 8 = 56 -> 56 = 56. Does 56 equal 56? Then yes, x = 6 is a solution of the equation 8x + 8 = 56.

For Part B, it changed the value of x from 6 to 9. It also states that the left side of the equation (left side of the equal sign) stays the same so it'll still be 8x + 8. You do what you did in Part A, but instead of inputting 6, you do 9. It'll be like this: 8(9) + 8. It's asking how the right side would change, but that's basically asking what the answer is. If you do the math correctly, it'd be 72+8, which would be 80. The right side would need to be 80 if the solution is now x = 9.

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Y_Kistochka [10]

The function f(x)=(x-2)^3+8 is one-to-one and the inverse of f(x) is f^{-1} (x)=(x-8)^\frac{1}{3}+2.

A function is one-to-one if for f(a)=f(b), we show that a=b.

f(a)=(a-2)^3+8

f(b)=(b-2)^3+8

Take f(a)=f(b)

(a-2)^3+8=(b-2)^3+8

(a-2)^3=(b-2)^3

Let A=a-2 and B=b-2

If A^3=B^3, then A=B.

So, a-2=b-2

a=b.

So, the function is one-to-one.

For the inverse of f(x), replace x with y and solve for y.

x=(y-2)^3+8

(y-2)^3=x-8

y-2=(x-8)^\frac{1}{3}

y=(x-8)^\frac{1}{3}+2

So, the inverse of f(x) is y=(x-8)^\frac{1}{3}+2.

Learn more about and inverse of a function here:

brainly.com/question/2541698?referrer=searchResults

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2 years ago
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