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2 years ago

Which linear function has the greater rate of change Y= 8x+ 3

Mathematics

1 answer:

Ad libitum [116K]2 years ago

6 0

17 bc I did it trust me pls

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HELPP!!!!!!!!!!!!!!!!

Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step. The equation is

$8-3\sqrt[5]{x^3}=-7$

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:

$-3\sqrt[5]{x^3}=-15$

The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:

$\sqrt[5]{x^3}=5$

Let's rewrite that radical into exponential form:

$x^{\frac{3}{5}}=5$

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

$(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}$

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:

$x=\sqrt[3]{5^5}$

Let's group that radicad into groups of 3's now to make the simplifying easier:

$x=\sqrt[3]{5^3*5^2}$ because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

$x=5\sqrt[3]{5^2}$ which is the same as:

$x=5\sqrt[3]{25}$

8 0

2 years ago

The cost of a school banquet is 75$ plus 15$ per person.

ivann1987 [24]

Answer:

The cost of a school banquet is $75+30n, where n is the number of people attending.

If 53 people are attending to visit school banquet, then you have to find the value of given expression at n=53.

At n=53, the value is $(75+30·53)=$1,665.

Step-by-step explanation:

4 0

2 years ago

NEED NOW!!

Vesnalui [34]

А??????????????????........

6 0

2 years ago

Zip codes for the Houston area are five digit numbers with 7 as the first 2 digits of each zip code. The third digit can be 0, 3

djyliett [7]

Answer:

There are 400 possible zip codes in the Houston area

Step-by-step explanation:

Here, we want to calculate the possible number of zip codes in the Houston area

We have 5 digits to form

77 is the first two digits ( this is fixed)

For the third digit, we are selecting 1 number out of 0,3,4 or 5

This means 4 C 1

The remaining digits can be any digits

We have 0-9, a total of 10 digits

The first will be 10 C 1 and the second last digit too is 10 C 1

So the number of possible zip codes will be;

4 C 1 * 10 C 1 * 10 C 1

= 4 * 10 * 10 = 400 possible zip codes

6 0

2 years ago

3w = 30 .... What is the solution of this equation?

uranmaximum [27]

Answer:

3w = 30

w = 30/3

therefore w = 10

8 0

2 years ago

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