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Anestetic [448]
3 years ago
12

What is the interquartile range of 1.3,2.7,4.5,3.5,1.5,3.7,2,2.4,3.1,2.7

Mathematics
1 answer:
swat323 years ago
6 0

Step-by-step explanation:

To find the IQR you need to find the median and the subtract the 3rd quartile from the 1st

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Prove that 25^9+5^17is divisible by 30
VLD [36.1K]

Answer:

proof is below

Step-by-step explanation:

Answer:

25^9 + 5^17=

=2^18 + 5^17

=5^17(5+1)

=5^17×6

=5^16×30  is divisible by 30

6 0
2 years ago
Evaluate n + m when n = -24 and y = 0.874.
Flauer [41]

Answer:

-24+m is correct answer

Step-by-step explanation:

In pic

(Credit : Symbolab)

(Hope this helps can i pls have brainlist (crown)☺️)

3 0
3 years ago
Given that f(x) = 6x + 2 and g(x) =2x+4 over 5 solve for g(f(1))
Lady bird [3.3K]
F(1)=6(1)+2
= 6+2
=8

g(f(1))= 2x/5 +4/5
= 2(8)/5 +4/5
= 16/5 +4/5
= 20/5
=4
6 0
3 years ago
7 2\3+ (5 1\6-1 5\9)
lorasvet [3.4K]
Start off with: 5 1/6 - 1 5/9
turn it into an entire fraction: 31/6 - 14/9
make a common denominator (which is 18): 93/18 - 28/18 = 93 - 28 = 65/18
65/18 + 7 2/3 is the new equation
7 2/3 = 23/3
23/3 = 138/18
65/18 + 138/18 = 203/18
Simplify: 203/18 = 11 5/18
Answer: 11 5/18  
3 0
3 years ago
Read 2 more answers
The average daily high temperature in Seattle is modeled by the function T = –15 cos(πm/6)+ 61, where T is the temperature in °F
Sliva [168]

Answer:

m = 6

Step-by-step explanation:

T = -15cos(\frac{\pi m}{6}) +61

76 = -15cos(\frac{\pi m}{6}) +61

76-61 = -15cos(\frac{\pi m}{6})

15 = -15cos(\frac{\pi m}{6})

\frac{15}{-15}  = cos(\frac{\pi m}{6})

-1  = cos(\frac{\pi m}{6})

cos^{-1}( -1)  = \frac{\pi m}{6}

\pi  = \frac{\pi m}{6}

6\pi  = \pi m

m = 6

7 0
2 years ago
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