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SIZIF [17.4K]
3 years ago
15

(a) Use differentiation to find a power series representation for

Mathematics
1 answer:
choli [55]3 years ago
8 0

Answer:1/(3+x)=(1/3)

1

(1−(−x/3))

1/(3+x)=(1/3)1(1−(−x/3))

Use this fact that  

1/(1−t)=

∑

∞

0

t

n

  (∗)

1/(1−t)=∑0∞tn   (∗)

where  

|t|<1

|t|<1

. I mean take  

t=−x/3

t=−x/3

and...

Note that  

|−t|=|t|<1

|−t|=|t|<1

is the radius of convergence

Step-by-step explanation:

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In a probability experiment, Eric flipped a coin 39 times. The coin landed on heads 26 times. What is the ratio of heads to tail
PilotLPTM [1.2K]

Answer:

26 : 13

Explanation:

Total # of times the coin was flipped: 39

# of heads: 26

39 - 26 = 13

# of tails: 13

Heads : Tails

26 : 13

4 0
3 years ago
For f(x) = 4x+ 1 and g(x) = x2 - 5, find (f+ g)(x).
horrorfan [7]

Answer:

x^2+4x-4

Step-by-step explanation:

4x+1+x^2-5

x^2+4x-4

6 0
4 years ago
Read 2 more answers
For the real-valued functions f(x)=2x+1 and g(x)=sqrt(x-1), find the composition f o g and specify its domain using interval not
Anettt [7]

Answer:

fog = 2√(x-1) + 1

Domain = [1, \infty)

Step-by-step explanation:

Given the functions  f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog

fog = f(g(x))

f(g(x)) = f(√(x-1))

f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)

f(√(x-1)) = 2(√(x-1))+1

f(√(x+1)) = 2√(x-1) + 1

fog = 2√(x-1) + 1

<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>

If x-1≥0

x≥0+1

x≥1

This means the range of variable x must be values of x greater than or equal to 1.

Domain = [1, \infty)

8 0
3 years ago
PLEASE HELP
Murrr4er [49]
20% decrease should be the answer
3 0
3 years ago
Peter is wants to lose weight. He is105Kg. His aim is to lose 500 g Per week. If he managed this, how many weeks will it be unti
natali 33 [55]

105 - 90 = 15kg

500g = 1/2 kg

Peter is 15kg overweight.

15 x 2 = 30

It will take him 30 weeks for this.

8 0
3 years ago
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