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4 years ago

If you pay $5,500 for a simple interest note that will be worth $6,000 in 21 months,

Mathematics

2 answers:

natita [175]4 years ago

7 0

Answer:

5.19%

Step-by-step explanation:

The amount of an account (A) earning simple interest rate r for time t on principal P is ...

A = P(1 +rt)

Filling in the given values and solving for r gives ...

6000 = 5500(1 +r(21/12))

12/11 = 1 + r(7/4) . . . . . . . . . . divide by 5500, simplify fractions

1/11 = r(7/4) . . . . . . . . subtract 1

4/77 = r . . . . . . . . . . . multiply by 4/7

r ≈ 0.051948 ≈ 5.19%

You will be earning about 5.19% annual simple interest.

avanturin [10]4 years ago

5 0

Answer: The annual simple interest rate is 5.19%

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the simple interest note.

P represents the principal or amount paid for the simple interest note.

R represents interest rate

T represents the duration in years.

From the information given,

P = 5500

T = 21 months = 21/12 = 1.75 years

I = 6000 - 5500 = $500

500 = (5500 × R × 1.75)/100

500 = 9625R/100 = 96.25R

R = 500/96.25

R = 5.19%

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3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

$y = -16x^2 + 177x + 98$

It hits the ground when $y = 0$ , so we have to find x for which $y = 0$ , which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$y = -16x^2 + 177x + 98$

$-16x^2 + 177x + 98 = 0$

$a = -16, b = 177, c = 98$

$\bigtriangleup = 177^{2} - 4(-16)(98) = 37601$

$x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53$

$x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59$

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

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3 years ago