Two number cubes are rolled. What is the probability that the first lands on an odd number and the second lands on an even numbe
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Greetings from Brasil...
Here we have an indeterminacy 0/0
We can change variable or rationalize.......
Let's rationalize
{[√(X + 4) - 2]/X} · {[√(X + 4) + 2]/[√(X + 4) + 2]} = 1/[√(X + 4) + 2]
So, the limit will be 1/4
