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love history [14]

3 years ago

15

Two number cubes are rolled. What is the probability that the first lands on an odd number and the second lands on an even numbe

r? Enter your answer as a fraction in simplified form, in the box.

1 answer:

Tems11 [23]3 years ago

3 0

9/18 or 1/2 would be the answer

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Prime time factorization<br> multiples of 63.

11111nata11111 [884]

63 = 3,3,7 = 3squared,7

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3 years ago

Please help me fast .!!!

zhannawk [14.2K]

Answer:

it would be 5,4

Step-by-step explanation:

go to 5 the to 4 wich would then lead you to 5,4

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3 years ago

4[q + 5]=<br><br> whats the answer??

Snezhnost [94]

Answer:

4q+20

I used the distributive property.

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3 years ago

Read 2 more answers

Tim has twice as many marbles as Luke together they have 39 marbles how many marbles does time have

mash [69]

Luke has 13 and Tim has 26, Tim has twice has many marbles as Luke which would be 13 times 2, 26+13=39

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3 years ago

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What is y=4x^2-9x+1 in vertex form

Anna11 [10]

Answer:

$y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}$

Step-by-step explanation:

$y = 4x^2 - 9x + 1$

You need to complete the square on the right side.

$y = (4x^2 - 9x) + 1$

$y = 4(x^2 - \dfrac{9}{4}x) + 1$

$y = 4 \left( x^2 - \dfrac{9}{4}x + \left( \dfrac{9}{8} \right)^2 \right) + 1 - 4\left( \dfrac{9}{8} \right)^2$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - 4 \left( \dfrac{81}{64} \right)$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - \dfrac{81}{16}$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + \dfrac{16}{16} - \dfrac{81}{16}$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}$

3 0

3 years ago