10. For f(x) = 3 - 5x, find f(-5). A. –22 B. -7 C. 3 D. 28

Find the area of a triangle with sides of length 6 and 7 and included angle 74°. (round your answer to one decimal place.)

Yanka [14]

We use this formula:
Area = ½ • side 1 • sine (A) • side 2
Area = ½ • 6 • sine (74) • 7
Area = 21 • sine (74)
Area = 21*0.96126
Area = 20.18646 
Area = 20.2 (rounded)
Source:
http://www.1728.org/triang.htm

5 0

3 years ago

How do you write 1 over 100 as a power of 10 with a negative exponent?

vaieri [72.5K]

I think it would look like this 1/100^-10 hope dis helped

7 0

3 years ago

Read 2 more answers

How do you solve this?

solong [7]

It looks like your equations are

7M - 2t = -30

5t - 12M = 115

Solving by substitution

Solve either equation for one variable. For example,

7M - 2t = -30 ⇒ t = (7M + 30)/2

Substitute this into the other equation and solve for M.

5 × (7M + 30)/2 - 12M = 115

5 (7M + 30) - 24M = 230

35M + 150 - 24M = 230

11M = 80

M = 80/11

Now solve for t.

t = (7 × (80/11) + 30)/2

t = (560/11 + 30)/2

t = (890/11)/2

t = 445/11

Solving by elimination

Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,

7M - 2t = -30 ⇒ -10t + 35M = -150 … (multiply by 5)

5t - 12M = 115 ⇒ 10t - 24M = 230 … (multiply by 2)

Now combining the equations eliminates the t terms, and

(-10t + 35M) + (10t - 24M) = -150 + 230

11M = 80

M = 80/11

It follows that

7 × (80/11) - 2t = -30

560/11 - 2t = -30

2t = 890/11

t = 445/11

4 0

2 years ago

Jack wanted to measure the weight of his luggage at the airport before departure. He was surprised to see that it weighed 23.6 k

Alex

Answer:

25.7 is how much his luggage weighs.

Step-by-step explanation:

4 0

2 years ago

A survey of 1,562 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying techn

tester [92]

Answer:

a) We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

b) $z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

c) $p_v =2*P(z$

d) Null hypothesis: $p=0.35$

e) Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

Step-by-step explanation:

Information provided

n=1562 represent the random sample selected

X=522 represent the people who have heard of a new electronic reader

$\hat p=\frac{522}{1562}=0.334$ estimated proportion of people who have heard of a new electronic reader

$p_o=0.35$ is the value to verify

$\alpha=0.05$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Part a

We want to test the claim that 35% of adults have heard of the new electronic reader, then the system of hypothesis are.:

Null hypothesis: $p=0.35$

Alternative hypothesis: $p \neq 0.35$

And is a two tailed test

Part b

The statistic for this case is given :

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.334 -0.35}{\sqrt{\frac{0.35(1-0.35)}{1562}}}=-1.326$

Part c

We can calculate the p value using the laternative hypothesis with the following probability:

$p_v =2*P(z$

Part d

The null hypothesis for this case would be:

Null hypothesis: $p=0.35$

Part e

The best conclusion for this case would be:

Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha.

5 0

3 years ago