Given:
A man owns 3/4 of the share of a business and sells 1/3 of his shares for Bir 10,000.
To find:
The value of the business in Bir.
Solution:
Let x be the value of the business.
It is given that a man owns 3/4 of the share of a business and sells 1/3 of his shares for Bir 10,000.
![x\times \dfrac{3}{4}\times \dfrac{1}{3}=10000](https://tex.z-dn.net/?f=x%5Ctimes%20%5Cdfrac%7B3%7D%7B4%7D%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%3D10000)
![x\times \dfrac{1}{4}=10000](https://tex.z-dn.net/?f=x%5Ctimes%20%5Cdfrac%7B1%7D%7B4%7D%3D10000)
Multiply both sides by 4.
![x=4\times 10000](https://tex.z-dn.net/?f=x%3D4%5Ctimes%2010000)
![x=40000](https://tex.z-dn.net/?f=x%3D40000)
Therefore, the value of the business is 40,000 Bir.
Answer:
The answer is<u> D.</u> h+3/j+6.
Step-by-step explanation:
Given:
The equation h + 3 = jk + 6k.
Now, to get the mathematical expression.
![h + 3 = jk + 6k](https://tex.z-dn.net/?f=h%20%2B%203%20%3D%20jk%20%2B%206k)
So, taking
common on R.H.S we get:
![h + 3 = k(j + 6)](https://tex.z-dn.net/?f=h%20%2B%203%20%3D%20k%28j%20%2B%206%29)
Then, dividing both sides by
we get:
![\frac{h+3}{j+6} =k](https://tex.z-dn.net/?f=%5Cfrac%7Bh%2B3%7D%7Bj%2B6%7D%20%3Dk)
Thus,
![k=\frac{h+3}{j+6}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7Bh%2B3%7D%7Bj%2B6%7D)
Therefore, the answer is D. h+3/j+6.
Answer:
Step-by-step explanation:
Answer:
<h3>Total 20 boxes are there. </h3>
Step-by-step explanation:
Total number of shelves in a warehouse = 5 shelves.
Each shelve either can hold maximum 8 boxes with their lengths or can hold 4 boxes with their heights.
So, in that case only 4 boxes could be hold in each of 5 shelves because only 4 boxes could be fit with their heights.
Therefore, total number of boxes = 5 × 4 = 20 boxes .
<h3>Therefore, total 20 boxes are there. </h3>
Answer:
$3.75
Step-by-step explanation:
$12.50-$8.75=$3.75
Hope this helps!