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Bogdan [553]
3 years ago
8

What is the probability of the uppermost faces do not sum to five and are not a product of 4 ?

Mathematics
1 answer:
Yanka [14]3 years ago
5 0
The probability of the uppermost faces is 34
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Please helpp due soon!! 10 points :)
zubka84 [21]

Answer:

2.3\:\mathrm{in^3},\\1.3\:\mathrm{fl\:oz}

Step-by-step explanation:

The volume of a cone with radius r and height h is equal to V=\frac{1}{3}\cdot r^2\pi\cdot h.

What we're given:

  • Since radius is half the diameter, r is 1.1
  • Height of 1.8

Substituting given values, we get:

V=\frac{1}{3}\cdot 1.1^2\pi \cdot 1.8=0.726\pi\approx \boxed{2.3\:\mathrm{in^3}}

Convert to fluid ounces using the conversion given in the question:

0.726\pi}\cdot \frac{0.554}{1}\approx \boxed{{1.3\:\mathrm{fl\:oz.}}}

5 0
3 years ago
{This question has been deleted}
stiks02 [169]

Answer:

this question isn't deleted yet

4 0
2 years ago
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What is one quality of rotation
Sunny_sXe [5.5K]

Answer:

Quality rotation is the act of a joint moving through a range of motion in a way that is efficient, controlled and repeatable.

8 0
2 years ago
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Suppose you want to fence in some land along the edge of a straight river. the fenced area will be in the shape of a rectangle,
m_a_m_a [10]
For the largest area, half the fence is used parallel to the river, and the other half is used for the two ends of the rectangular space.

The dimensions are 475 m by 237.5 m.

_____
Let x represent the length along the river. Then the area (A) is found as
.. A = x*(950 -x)/2
This equation describes a parabola with its vertex (maximum) halfway between the zeros of x=0 and x=950. That is, the maximum area is achieved when half the fence is used parallel to the river.

7 0
3 years ago
Instructions: Use the ratio of a 30-60-90 triangle to solve for the variables.
Pepsi [2]

Answer:

x=20

y=10\,\sqrt{3}

Step-by-step explanation:

In the triangle we have the following trigonometric equations:

tan(60^o)=\frac{opposite}{adjacent} \\\sqrt{3} =\frac{y}{10} \\y=10\,\sqrt{3}

and also:

cos(60^o)=\frac{adjacent}{hypotenuse}\\\frac{1}{2} =\frac{10}{x}\\x=20

8 0
3 years ago
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