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Bogdan [553]
3 years ago
8

What is the probability of the uppermost faces do not sum to five and are not a product of 4 ?

Mathematics
1 answer:
Yanka [14]3 years ago
5 0
The probability of the uppermost faces is 34
You might be interested in
Please show your work! Thankyou!
ZanzabumX [31]
Log₄(y+2) = 3, transform it into exponent form:

(y+2) = 4³
y+2 = 64
 y= 62

5 0
3 years ago
2) Kari is flying her kite at the park. She has let
Ket [755]

Answer:

approx 58 yard we can determine it by pithagoras theorem

6 0
3 years ago
a landscaping company counted 51 invoices for tree services at the end of the month. they charge $375 for a tree installation an
Radda [10]

We used the elimination method to find the ordered pair, (x,y), that represents the situation is (12,39).

Number of invoices = 51

Charge for tree installation = $375

Charge for tree trimming = $54

Total amount in invoices = $6,606

Let x and y represent number of installations and number of trimmings respectively.

Hence,

x + y = 51  ...(1)

375x + 54y = 6606

3 (125x + 18y) = 3*2202

125x + 18y = 2202  ...(2)

Multiplying (1) by 18, we get

18x + 18y = 918  ...(3)

(2) - (3)

107x + 0 = 1284

x = 1284/107 = 12

Hence,

y = 51 - 12 = 39.

To learn more about elimination method, here:-

brainly.com/question/13877817

#SPJ4

3 0
1 year ago
An air transport association surveys business travelers to develop quality ratings for transatlantic gateway airports. The maxim
Flura [38]

Answer:

The 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population mean, when the population standard deviation is not provided is:

CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}

The sample selected is of size, <em>n</em> = 50.

The critical value of <em>t</em> for 95% confidence level and (<em>n</em> - 1) = 49 degrees of freedom is:

t_{\alpha/2, (n-1)}=t_{0.05/2, 49}\approx t_{0.025, 60}=2.000

*Use a <em>t</em>-table.

Compute the sample mean and sample standard deviation as follows:

\bar x=\frac{1}{n}\sum X=\frac{1}{50}\times [1+5+6+...+10]=6.76\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{49}\times 31.12}=2.552

Compute the 95% confidence interval estimate of the population mean rating for Miami as follows:

CI=\bar x \pm t_{\alpha/2, (n-1)}\cdot \frac{s}{\sqrt{n}}

     =6.76\pm 2.000\times \frac{2.552}{\sqrt{50}}\\\\=6.76\pm 0.722\\\\=(6.038, 7.482)\\\\\approx (6.0, 7.5)

Thus, the 95% confidence interval estimate of the population mean rating for Miami is (6.0, 7.5).

7 0
3 years ago
Someone help me please I'm so desperate
ludmilkaskok [199]

Answer:

126 tiles

Step-by-step explanation:

The while tiles are 3/4 of a foot (or 9 inches) x 9 in, so their area is 81 sq in. There are 14 blue tiles, so 14 x 81 = 1134 sq inches that need to be covered.

Each tiles is 3 x 3, so its area is 9 sq in. 1134 / 9 = 126 tiles

6 0
2 years ago
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