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bogdanovich [222]
2 years ago
14

Jason has 52 toy cars. His friend Jonathan has only 24. How many cars should Jason give to Jonathan so that they have the same n

umber of toy cars? What would that number be?

Mathematics
2 answers:
diamong [38]2 years ago
4 0

Answer:

its 28 because you can't subtract 4 from 2 so you crops out the 2 and change it two 12 then subtract 12-4 which equals 8 so now you move on two 5-2 which some you would think is 3 because 5-2 is 3 but what you do is cross out five and change it to 4 finally do 4-2 which equals 2 so 28 is ur answer.

jekas [21]2 years ago
4 0

Answer:

14

Step-by-step explanation:

Start by finding the average number of cars owned by both boys:

52 + 24

------------ = 76/2 = 38.

      2

Subtract 24 from 38, obtaining 14.  Adding 14 cars to Jon's 24 yields 38 cars.

Adding 14 to this 38 yields 52 (which verifies that this math is correct).

Jason should give Jon 14 cars.  The the two boys would have the same number of cars.

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NEED HELP ASAP<br> Given G (-6,5) and H (2, -7), what is the length of GH
lesya692 [45]

\bold{\huge{\green{\underline{ Solution }}}}

\bold{\underline{ Given}}

  • <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

\bold{\underline{To  \: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

\bold{\underline{Let's \:  Begin :- }}

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}

  • <u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}

\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}

\sf{Distance\:GH=√(-8)^2+(12)^2}

\sf{ Distance \:GH =√64 + 144 }

\sf{ Distance \:GH =√ 208}

\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}

\sf{ Distance \:GH = 4√13}

\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}

3 0
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What are the solutions to the quadratic equation (5y + 6)2 = 24?
lana [24]
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6 0
2 years ago
Read 2 more answers
Just number 14 please
larisa [96]
Nope you posted this five days ago no need for another answer.
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