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serious [3.7K]
4 years ago
7

Which of the following is a postzygotic isolating barrier?

Biology
1 answer:
Jet001 [13]4 years ago
8 0

Answer: The following is a <u>postzygotic isolating barrier </u>:

  • The hybrid offspring of two species of crocodiles can produce normal gametes but cannot obtain a mate.  

Explanation:

<em><u>Reproductive isolation </u></em>occurs when <em>barriers prevent</em> two populations from interbreeding , <u>keeping their gene pools separate.</u>

We can find the Prezygotic isolation that occurs<u> before fertilization </u>can happen.

And the Postzygotic insolation barriers are the reproductive insulation processes that<u> act after the mating</u>. They are all that concern the viability of the individuals produced.

Prezygotic isolation barriers can be temporal, behavioural, geographic , ecological or mechanical; whereas postzygotic isolation barriers include the inviability, infertility or breakdown of hybrid organisms

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What type of graph is a and b please help me​
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you can chose to describe the second graph as any of the following phrases:

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2 years ago
Bacteria and other microbes can be used to "clean up" an oil spill by breaking down oil into carbon dioxide and water. Two sampl
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Answer:

For sample A, A=17.7 %, T=17.7 %, G=32.30%, C=32.30%

For sample B, A= 28.9%, T=28.9%, G= 21.10%, C= 21.10%

Explanation:

The composition of nitrogenous bases in DNA is calculated using the suggestions proposed by the results of the experiment performed by Erwin Chargaff.

He found that in a DNA sample the composition of purine to pyrimidine is 1:1. This indicates that the amount of purine equals pyrimidine. This can be presented as purines + pyrimidines= 100. Also, adenine binds thymine and cytosine binds guanine.

In the given question,  

<u>For sample A </u>

A= 17.7 %, Therefore, thymine will be = 17.7 %,

A+T= 35.40%

Now, G+C=100- 35.40%

G+C= 64.60%

content of G= 64.60/2= 32.30%

content of C= 32.30%

<u>For sample B </u>

T=28.9%, A will be= 28.9%

A+T= 57.80%

G+C=100-57.80%

G+C= 42.20%

Thus content of G will be= 42.20/2=21.10

content of C= 21.10%

Thus,  

For sample A, A=17.7 %, T=17.7 %, G=32.30%, C=32.30%

For sample B, A= 28.9%, T=28.9%, G= 21.10%, C= 21.10%

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4 years ago
What general surgical techniques are necessary for a live donor kidney transplant?
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suppose you are studying a fruit fly's DNA and you discover a gene for antenna length on chromosome 2. what word describes its l
soldier1979 [14.2K]

Answer:

<h2>In all flies,on the same Locus, on chromosome 2 at the same place you find the gene for antenna length.</h2>

Explanation:

In all fruit flies ,on the same  Locus, on chromosome 2 at the same place you find the gene for antenna length

All fruit flies contain same amount of gene and chromosomes, so the location of all gene in all fruit flies found at the same location.

A gene for antenna length in all fruit flies on chromosome 2 is present on same the location.

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