Answer: point V' is located at (3,-1)
To solve this problem you must apply the proccedure shown below:
1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
(y^2/a^2)+(x^2/b^2)=1
2. You have the distance from the center of the ellipse to the focus:
c=12, therefore, you can calculate the value of b, the minor radius:
c^2=a^2-b^2
b=√(13^3-12^2)
b=5
3. Therefore, the equation is:
a^2=169
b^2=25
(y^2/169)+(x^2/25)=1
The answer is: (y^2/169)+(x^2/25)=1
Answer:
23+12=
Step-by-step explanation:
you just need figure it out in your head and see what sounds right
Which set of ordered pairs represents a function? {(0, 1), (1, 3), (1, 5), (2, 8)} {(0, 0), (1, 2), (2, 6), (2, 8)} {(0, 0), (0,
11111nata11111 [884]
Answer: {(0, 2), (1, 4), (2, 6), (3, 6)}
Step-by-step explanation:
For a relation to be considered a function, each x-value needs to have one corresponding y-value--it cannot have more than 1.
Since all the other sets of ordered pairs feature points with two x-values with different y-values, the set above is the only function of the provided options.
Answer:
x=2
Step-by-step explanation:
We know the only number that gets us back to 0 after subtracting 4 is 4, because 4-4=0. The square root of 4 is 2. Hope my explanation wasn't too confusing!
2²=4
4-4=0
