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Vinvika [58]
3 years ago
14

Help please, thinking it's C

Mathematics
1 answer:
Fantom [35]3 years ago
4 0
I am not sure, but my answer is (a). However, I also think its (c), but mainly (a). Please tell me if I was incorrect. I'm sorry. Hope I helped.
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Solve for in the equation = .
Bad White [126]

Answer:

What's the equation?

Step-by-step explanation:

4 0
2 years ago
Subtract express your answer in simplest form 5/8-3/8=?
olchik [2.2K]
The answer is 2/8. Hope this helps.
6 0
3 years ago
Read 2 more answers
Awarding 90 Points
Amanda [17]

Answer:

  • 1090

Step-by-step explanation:

<h3>Given AP </h3>
  • a₁₂ = 62
  • a₂₀ = 102
<h3>To find</h3>
  • S₂₀
<h3>Solution</h3>
  • a₁₂ = a + 11d = 62
  • a₂₀ = a + 19d = 102

<u>Subtract the first equation from the second one:</u>

  • 8d = 40
  • d = 5

<u>Find a:</u>

  • a + 11*5 = 62
  • a = 62 - 55
  • a = 7

<u>Find the sum of the first 20 terms:</u>

  • S₂₀ = 1/2*20(a + a₂₀) = 10(7 + 102) = 10(109)= 1090

5 0
2 years ago
Please help urgent!!!<br> does 3 3/10 + 2 4/5 + 2 1/10 = 8.2?
Advocard [28]

Answer:

Yes

Step-by-step explanation:

Yes, 3 3/10 + 2 4/5 + 2 1/10 is equal to 8.2 because 3 3/10 + 2 4/5 + 2 1/10 is 41/5 and that into a mixed number is 8 1/5 and THAT into a decimal is 8.2

Hope this helped!

4 0
3 years ago
Consider a point on the trans-australian highway, where two old wombats live. arrivals of cars at this point follow a poisson di
mafiozo [28]
Given that the arrivals of cars at the trans-australian highway follow a poisson distribution with the average rate of arrivals as 1 car per 12 seconds.

This is a Poisson distribution with a mean of 1 car every 12 seconds.

Part A:

The probability of a Poisson distribution is given by:

P(X=x)= \frac{e^{-\lambda}\lambda^x}{x!}

Given tha one of the old wombats requires 12 seconds to cross the highway, and he starts out immediately after a car goes by. <span>

The probability he will survive is the probability that no car passes through the point in the next 12 seconds.

P(x=0)= \frac{e^{-1}(1)^0}{0!} =e^{-1}=0.368

Therefore, the probability that he will survive is 0.368



Part B:

Given that </span>at the same point of the highway there is another old wombat, slower but tougher than in the previous exercise. He requires 24 seconds to cross the road, but it takes two cars to kill him. (A single car won’t even slow him down. The arrival rate of cars is still one car per 12 seconds.)

Since the arrival rate of cars is one car per 12 seconds, then, in 24 seconds the arrival rate is 2 cars. (i.e. λ = 2)

T<span>he probability that he survives is the probability that 2 cars did not pass through the point.

P(X\neq2)=1-P(X=2)=1- \frac{e^{-2}(2)^2}{2!} =1-0.135=0.865</span>
6 0
3 years ago
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