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ser-zykov [4K]
4 years ago
15

Find the measurement indicated. Round your answers to the nearest tenth. Use Law of Sines​ or Cosines

Mathematics
2 answers:
tatuchka [14]4 years ago
3 0

Answer:

5. 34°

6. 29.7

Step-by-step explanation:

5. Using sine law

25/sin(93) = 14/sin(C)

sin(C) = 0.5592325395

C = 34.00273934°

6. Using cosine law

AC² = 23.2² + 18.1² - 2(23.2)(18.1)cos(91)

AC² = 880.507229

AC = 29.67334206

AveGali [126]4 years ago
3 0

Answer:

5. m∠C ≈ 34°

6. AC ≈ 29.7 metres

Step-by-step explanation:

5. We need to use the Law of Sines here, which says that for a triangle with sides a, b, and c and angles A, B, and C:

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

Here, a = 25, ∠A = 93°, and c = 14, so we want to find ∠C:

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

\frac{25}{sin93} =\frac{14}{sinC}

sinC ≈ 0.56

∠C ≈ 34°

6. We need to use the Law of Cosines here, which says that for a triangle with sides a, b, and c and angles A, B, and C:

c^2=a^2+b^2-2abcosC

b^2=a^2+c^2-2accosB

a^2=b^2+c^2-2bccosA

Here, a = 23.2, c = 18.1, ∠B = 91°, and b = x. We want to find b, so:

b^2=a^2+c^2-2accosB

x^2=23.2^2+18.1^2-2*23.2*18.1*cos(91) ≈ 880.5

x ≈ 29.7 metres

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The complete question is
Three tennis balls are stored in a cylindrical container with a height of 8 inches and a radius of 1.43 inches. The circumference of a tennis ball is 8 inches. a) Find the volume of a tennis ball b) There are 3 tennis ball in the container Find the amount of space within the cylinder not taken up by the tennis balls. Round your answers to the nearest hundredth.

Part a) 

we know that
length of a circumference=2*pi*r----------> r=length/(2*pi)---> 8/(2*pi)
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volume of a tennis ball is equals to the volume of a sphere
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Part b)
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the answer Part b) is
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