A sandwich shop has 60 stores and 80% of the stores are in California. The rest of the stores are in Nevada.
1 answer:
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This is the answer.
-4,0
Answer:
(2, 0)
Step-by-step explanation:
To solve this problem, we have to plot a graph. A graph was plotted using geogebra online graphing calculator. From the attached graph we can see the points that satisfy the constraints: (0,0), (2, 0), (2, 6), (6, 4). But since x,y > 0, this leaves us with B(2, 6), C(2, 0), D(6, 4)
The cost equation is C = 3x + 4y
At point B(2, 6): C = 3(2) + 4(6) = 30
At point C(2, 0): C = 3(2) + 4(0) = 6
At point D(6, 4): C = 3(6) + 4(4) = 34
Therefore the minimum cost is at C(2, 0)
Answer:
The correct answer is :
1. Line PQ (One line PQ).
Step-by-step explanation:
The first step to solve this question is to draw the plane A with the points P and Q lying on it.
We know that given two different points there is only one line that contains this two different points.
Let's analyze each option.
''2. Lines PQ and QP''
This option is wrong because there aren't two different lines. In fact it is only one line that can be named line PQ or line QP.
''3. The 2 lines PQ and QP plus another line that does not lie in plane A.''
This option is assuming that exist three lines that contain P and Q. This option is also wrong.
''1. Line PQ''
This option is correct. It will be clarify with the drawing I will attach.
''We can't name them all!''
This option is assuming that exist infinite lines that contain P and Q. This option is wrong.
In the drawing I call the line that contains P and Q as line L.
Given that P and Q lie in plane A necessarily the line L must lie on the plane A.
