Consider the table representing a rational function.

Mathematics

2 answers:

g100num [7]3 years ago

8 0

Answer:

The function has a hole when x = 0 and a vertical asymptote when x = 4.

Step-by-step explanation:

ratelena [41]3 years ago

4 0

Answer:

The function has a hole when $x=0$ and a vertical asymptote when $x=4$ .

Step-by-step explanation:

We have been given a table that represents values of a rational function. We are asked to choose the statement that describes the graph of the function.

We can see from our given table that at $x=0$ and $x=4$ function is undefined.

We can also see that that the value of function to the left of 0 is $-0.244$ and the value of function to the right of 0 is $-0.256$ . This means that function has a point discontinuity that is at $x=0$ is zero for both numerator and denominator. Therefore, the function has hole at $x=0$ .

Upon looking at table we can see the value of function to the left of 4 is $-100$ and the value of function to the right of 4 is $100$ . This means that function is approaching to different directions around $x=4$ . Therefore, the function has a vertical asymptote at $x=4$ .

Therefore, option D is the correct choice.

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Mary is preparing for her college entrance exams in a practice test she answered 12 problems in 30 minutes at this rate how many

kap26 [50]

Answer:

40 problems in 100 minutes

Step-by-step explanation:

This is a ratio problem.

You first divide 30 minutes by three to get how many problems she can do in 10 minutes. What you do to one side you do to the other side. So then, you should have 4 problems in 10 minute. Then, you multiply 10 by 10 and 4 by 10 to get 40 problems in 100 minutes.

6 0

4 years ago

X2 =5. What is the answer for X

grin007 [14]

Answer:

x=2.5

Step-by-step explanation:

First, you do 5 divided by 2, because you are trying to find a missing factor. After that, your answer, which is 2.5, is what x equals.

Hope that helps!

7 0

4 years ago

Read 2 more answers

Differentiate y = 8x/ 3 − tan(x)

vagabundo [1.1K]

Answer:

$\frac{dy}{dx}=\frac{8(xsec^2(x)-tan(x)+3)}{(3-tan(x))^2}$

Step-by-step explanation:

$y=\frac{8x}{3-tan(x)}\\ \\\frac{dy}{dx}=\frac{(3-tan(x))(\frac{d}{dx}8x)-(\frac{d}{dx}(3-tan(x)))(8x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{(3-tan(x))(8)-(-sec^2(x))(8x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{24-8tan(x)+8xsec^2(x)}{(3-tan(x))^2}\\ \\ \frac{dy}{dx}=\frac{8xsec^2(x)-8tan(x)+24}{(3-tan(x))^2}\\\\ \frac{dy}{dx}=\frac{8(xsec^2(x)-tan(x)+3)}{(3-tan(x))^2}$