From point A, draw a line segment at an angle to the given line, and about the same length. The exact length is not important. Set the compasses on A, and set its width to a bit less than one fifth of the length of the new line. Step the compasses along the line, marking off 5 arcs. Label the last one C. With the compasses' width set to CB, draw an arc from A just below it. With the compasses' width set to AC, draw an arc from B crossing the one drawn in step 4. This intersection is point D. Draw a line from D to B. Using the same compasses' width as used to step along AC, step the compasses from D along DB making 4 new arcs across the line. Draw lines between the corresponding points along AC and DB. Done. The lines divide the given line segment AB in to 5 congruent parts.
We effectively rewrite the equation as
In order for the LHS to be defined, we need to restrict 
, or 
. Now, the LHS will vanish when the numerator is 0, which happens for
This value is indeed smaller than 4, so the solution is 
.
The answer is 50% if you are just choosing between 2 cards and NOT the whole deck. Please mark most brainliest!
Answer:
45
Step-by-step explanation:
3 and 5 both go into 45 and 45 is the smallest for it
