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3 years ago

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When david emptied the collection canister of his vacuum cleaner, he found nickels and quarters among the other of the canister.

When he counted the coins, he found that the number of quarters he counted was three less than number of nickels he counted. He has 21 coins in all.

1 answer:

Ugo [173]3 years ago

5 0

he has 9 quarters and 12 nickles.

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The proof shows that opposite angles of a parallelogram are congruent. Given: ABCD is a parallelogram with diagonal AC. Prove: ∠

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A parallelogram is a figure which has its <em>opposite</em> sides to be <u>equal</u> and <u>parallel</u>. The <em>missing</em> reason in the proof is:

B. Substitution Angle Angle Postulate.

A <em>parallelogram</em> is a type of quadrilateral that has its <u>opposite</u> sides to be equal and parallel. The sum of its <em>internal</em> angles is $360^{o}$ .

To <u>prove</u> that ∠ BAD ≅ ∠ DCB, we have:

Given parallelogram ABCD;

<BAC ≅ <ACD (alternate angle theorem)

<DAC ≅ <ACB (alternate angle theorem)

<BAC + <DAC = <BAD

Also,

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Therefore,

<BAD ≅ <DCB (Substitution Angle Angle Postulate)

Thus, the <u>missing</u> reason in the partial proof is:

option B. Substitution Angle Angle Postulate

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Answer:

29

Step-by-step explanation:

180-151=29

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2 years ago

100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!

Volgvan

Using weighed averages, it is found that:

The final grade is 91.
The final grade is 66.8.
The higher grade would be 79.55, with the second grading scheme.
On average, she sold $48,280 per day.
On average, she makes $12.5 per hour.

---------------------------------------

To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

Grade of 91, with a weight of 67%.
Grade of 91, with a weight of 33%.

Thus:

$F = 91\times0.67 + 91\times0.33 = 91$

The final grade is 91.

---------------------------------------

Question 2:

Grade of 83, with a weight of 40%(highest grade).
Grade of 60, with a weight of 30%.
Grade of 52, with a weight of 30%.

Thus:

$F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8$

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

75 with a weight of 25%.
80 with a weight of 10%.
85 with a weight of 40%.
62 with a grade of 25%.

Thus:

$F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25$

---------------------------------------

With teacher 2:

75 with a weight of 15%.
80 with a weight of 10%.
85 with a weight of 60%.
62 with a weight of 15%.

Thus:

$F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55$

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

Average of $36,432, with a weight of $\frac{3}{3+10} = \frac{3}{13}$
Average of $51,834, with a weight of $\frac{10}{13}$

Thus:

$A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280$

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

Average of $14.84, with a weight of $\frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}$
Average of $10.76, with a weight of $\frac{4}{7}$

Thus:

$A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5$

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

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2 years ago