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natali 33 [55]
3 years ago
8

HELP ME PLEASE!! im being timed :(

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

Answer:

the first one and the third one

Step-by-step explanation:

ss7ja [257]3 years ago
7 0
6^-2
1^6^-2
“^” this means to the power
You might be interested in
The number of students of 7 more than 5 times the number of teacher. there are 12 theacher. how many students are there?
Alborosie

students =7+5*teachers

students = 7+5*12

students = 7+60

students = 67

5 0
3 years ago
I need help on this please help me
lbvjy [14]

Answer:

(0,-4-4√6) and (0,-4+4√6)

Step-by-step explanation:

To determine the coordinates as Jon wants to place it 14 points away

√10^2+(a+4)^2 = 14

100+(a+4)^2 = 196

(a+4)^2 = 96

a+4 = ±√96

a+4 = ±4√6

a= -4±4√6

4 0
2 years ago
Read 2 more answers
Suppose that a password for a computer system must have at least 8, but no more than 12, characters, where each character in the
uranmaximum [27]

Part a)

There are 52 letters (26 lowercase and 26 uppercase), 10 digits, and 6 symbols. There are 52+10+6 = 68 different characters to choose from.

  • If there are 8 characters for this password, then we have 68^8 = 4.5716 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 68^9 = 3.1087 * 10^16 different passwords
  • If there are 10 characters, then we have 68^10 = 2.1139 * 10^18 different passwords
  • If there are 11 characters, then we have 68^11 = 1.4375 * 10^20 different passwords
  • If there are 12 characters, then we have 68^12 = 9.7748 * 10^21 different passwords

Adding up those subtotals gives

68^8+68^9+68^10+68^11+68^12 = 9.9207 * 10^21

different passwords possible.

<h3>Answer: Approximately 9.9207 * 10^21 </h3>

======================================================

Part b)

Let's find the number of passwords where we don't have a special symbol

There are 52+10 = 62 different characters to pick from

  • If there are 8 characters for this password, then we have 62^8 = 2.1834 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 62^9 = 1.3537 * 10^16 different passwords
  • If there are 10 characters, then we have 62^10 = 8.3930 * 10^17 different passwords
  • If there are 11 characters, then we have 62^11 = 5.2037 * 10^19 different passwords
  • If there are 12 characters, then we have 62^12 = 3.2263 * 10^21 different passwords

Adding those subtotals gives

62^8+62^9+62^10+62^11+62^12 = 3.2792 * 10^21

different passwords where we do not have a special character. Subtract this from the answer in part a) above

( 9.9207 * 10^21)  - (3.2792 * 10^21) = 6.6415 * 10^21

which represents the number of passwords where we have one or more character that is a special symbol. I'm using the idea that we either have a password with no symbols, or we have a password with at least one symbol. Adding up those two cases leads to the total number of passwords possible.

<h3>Answer: Approximately 6.6415 * 10^21</h3>

======================================================

Part c)

The answer from part a) was roughly 9.9207 * 10^21

It will take about 9.9207 * 10^21  nanoseconds to try every possible password from part a).

Divide 9.9207 * 10^21  over 1*10^9 to convert to seconds

(9.9207 * 10^21 )/(1*10^9) = 9,920,700,000,000

This number is 9.9 trillion roughly.

It will take about 9.9 trillion seconds to try every password, if you try a password per second.

------

To convert to hours, divide by 3600 and you should get

(9,920,700,000,000)/3600 = 2,755,750,000

So it will take about 2,755,750,000 hours to try all the passwords.

------

Divide by 24 to convert to days

(2,755,750,000)/24= 114,822,916.666667

which rounds to 114,822,917

So it will take roughly 114,822,917 days to try all the passwords.

------

Then divide that over 365 to convert to years

314,583.334246576

which rounds to 314,583

It will take roughly 314,583 years to try all the passwords

------------------------------

<h3>Answers:</h3>
  • 9.9 trillion seconds
  • 2,755,750,000 hours
  • 114,822,917 days
  • 314,583 years

All values are approximate, and are roughly equivalent to one another.

5 0
3 years ago
Which expression is equivalent to (f9)(5)?
Helga [31]

Answer:

i think it would be fx9x5

Step-by-step explanation:

sorry if its not write

8 0
3 years ago
Simplify (4 √ 14 + 4 √ 10 ) ( 3 √ 7 − 4 √ 5 )
Iteru [2.4K]

Answer:

4 sqrt(2) - sqrt(70)

Step-by-step explanation:

Simplify the following:

(4 sqrt(14) + 4 sqrt(10)) (3 sqrt(7) - 4 sqrt(5))

Factor 4 out of 4 sqrt(14) + 4 sqrt(10) giving 4 (sqrt(14) + sqrt(10)):

4 (sqrt(14) + sqrt(10)) (3 sqrt(7) - 4 sqrt(5))

(sqrt(10) + sqrt(14)) (3 sqrt(7) - 4 sqrt(5)) = sqrt(10) (-4 sqrt(5)) + sqrt(10)×3 sqrt(7) + sqrt(14) (-4 sqrt(5)) + sqrt(14)×3 sqrt(7) = -20 sqrt(2) + 3 sqrt(70) - 4 sqrt(70) + 21 sqrt(2) = sqrt(2) - sqrt(70):

Answer:  4 sqrt(2) - sqrt(70)

4 0
3 years ago
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