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2 years ago

What is the written form for (8,8)

Mathematics

1 answer:

Sav [38]2 years ago

5 0

Answer:

81 900 000 000 000 is 8.19 × 10¹³

Step-by-step explanation:

Write the first number 8.

Add a decimal point after it: 8.

Now count the number of digits after 8. There are 13 digits.

So, in standard form: 81 900 000 000 000 is 8.19 × 10¹³

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I need help with this asap please! Any help will be appreciated!

pantera1 [17]

Answer:

n=3

Step-by-step explanation:

64^(1/3)

Note that the exponent 1/3 given stands for the third root of the integer.

64^(1/3) =4

Check: 4 x 4 x 4 = 64

(By comparison of 64^(1/3) to 64^(1/n) means n= 3)

∜(64^(1/3)) =∜(4) = 1.41421356

The real number is

All the roots are:

1.41421356

1.41421356i

−1.41421356

−1.41421356i

4 is not a perfect 4th power.

7 0

2 years ago

An automobile firm wants to purchase either machine A or machine B. The intial cost of machines A and B are $40,000 and $50,000,

Fynjy0 [20]

Answer:

C. $118,000 and $110,000, respectively.

Step-by-step explanation:

Please consider the complete question.

An automobile firm wants to purchase either machine A or machine B. The intial cost of machines A and B are $40,000 and $50,000, respectively. The power consumption per year of machines A and B are 120 MWh and 100 MWh, respectively. The power cost is $40/MWh. The estimated operating and maintenance cost over 10 years is $30,000 for machine A and $20,000 for machine B.

First of all, we will find the amount spent on power consumption for 10 years by each machine as:

$\text{Machine A}=10\cdot 120(\$40)\\\text{Machine A}=\$48,000$

$\text{Machine B}=10\cdot \$100(\$40)\\\text{Machine A}=\$40,000$

Now, we will find overall cost of machines A and B by adding initial cost, power consumption for 10 years and maintenance cost as:

$\text{Overall cost of machine A}=\$40,000+\$48,000+\$30,000$

$\text{Overall cost of machine A}=\$118,000$

$\text{Overall cost of machine B}=\$50,000+\$40,000+\$20,000$

$\text{Overall cost of machine B}=\$110,000$

Therefore, the overall cost of machines A and B are $118,000 and $110,000, respectively and option C is the correct choice.

6 0

3 years ago

1) Lithium isotope rations are important to medicine, the 6Li/7Li ratio in a standard reference material was measured several ti

uysha [10]

Answer:

1) $0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

b) $ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

Step-by-step explanation:

Information given

0.082601, 0.082621, 0.082589, 0.082617, 0.082598

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=0.0826052$ represent the sample mean

$\mu$ population mean

s=0.000013424 represent the sample standard deviation

n=5 represent the sample size

Part 1

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=5-1=4$

The Confidence level is 0.95 or 95%, and the significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ , the critical value would be using the t distribution with 4 degrees of freedom: $t_{\alpha/2}=2.776$

Now we have everything in order to replace into formula (1):

$0.0826052-2.776\frac{0.000013424}{\sqrt{5}}=0.082588$

$0.0826052+2.776\frac{0.000013424}{\sqrt{5}}=0.0826219$

Part 2

The original margin of error is given by:

$ME= 2.776\frac{0.000013424}{\sqrt{5}}=0.0000166653$

And we want 2/3 of the margin of error so then would be: $2/3 ME = 0.00001111$

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And on this case we have that ME =0.00001111016 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

$n=(\frac{z_{\alpha/2} s}{ME})^2$ (2)

Replacing we got:

$n=(\frac{2.776(0.000013424)}{0.00001111})^2 =11.25 \approx 12$

So the answer for this case would be n=12 rounded up to the nearest integer

3 0

3 years ago

PLEASE PLEASE HELP ME WITH THIS QUESTION PLEASE <br><br>AND SHOW YOUR STEPS PLEASE help me please

jeyben [28]

Answer:

4a)= 2.1m 4b)= 1.9 m 5)= 29.6º

Step-by-step explanation:

4a):

x is the opp

AB is the hyp

BC is the adj

thus,

sin32 = x/4

cross multiply, x= 4*sin32

x= 2.1196.......

x=2.1 m

4b).

x is the hyp

ac is the opp

bc is the adj

thus,

cos65=4.5/x

cross multiply, x= 4.5*cos65

x=1.9017....

x=1.9 m

5).

AB is the opp

bc is the adj

ac is the hyp

thus:

tanC= 2.1/3.7

C= tan^-1 (2.1/3.7)

C= 29.5778.....

C= 29.6º

5 0

2 years ago

Hey, I would love it it someone could please answer this as soon as possible!

Ann [662]

Answer:

Step-by-step explanation:

x= -1/4

3 0

2 years ago