Answer:
Step-by-step explanation:
the integers are -8,-7,-6,-5,-4,-3,
384/6 (amount of faces) = 64
64/2 (area= l*w) = 32
32*3 (volume=l*w*h) = 96
I'm pretty sure this is correct, maybe just double check and see if this makes any sense according to what you're learning? I'm almost 100% sure. Hope this helps!
I’m so sorry I would try my best to answer but I can’t :(
Heres a tip, multiply the numbers without any decimals then when done, add how many decimal places there are in total.
Ex:16.28 x 4 = 65.12
1625 x 4 = 6512
Yeeee
assuming your equaiton is
![2ln(e^{ln(2x)})-ln(e^{ln(10x)})=ln(30)](https://tex.z-dn.net/?f=2ln%28e%5E%7Bln%282x%29%7D%29-ln%28e%5E%7Bln%2810x%29%7D%29%3Dln%2830%29)
remember some nice log rules
![log_a(b)=c](https://tex.z-dn.net/?f=log_a%28b%29%3Dc)
translates to
![a^c=b](https://tex.z-dn.net/?f=a%5Ec%3Db)
and
![a^{log_a(b)}=b](https://tex.z-dn.net/?f=a%5E%7Blog_a%28b%29%7D%3Db)
and
![xlog_c(b)=log_c(b^x)](https://tex.z-dn.net/?f=xlog_c%28b%29%3Dlog_c%28b%5Ex%29)
and
![ln(x)=log_e(x)](https://tex.z-dn.net/?f=ln%28x%29%3Dlog_e%28x%29)
and
![log(a)-log(b)=log(\frac{a}{b})](https://tex.z-dn.net/?f=log%28a%29-log%28b%29%3Dlog%28%5Cfrac%7Ba%7D%7Bb%7D%29)
and
if
![log(a)=log(b)](https://tex.z-dn.net/?f=log%28a%29%3Dlog%28b%29)
then a=b
so
we can simplify a bit of stuff here
the
![e^{ln(2x)} \space\ and \space\ the \space\ e^{ln(10x)}](https://tex.z-dn.net/?f=e%5E%7Bln%282x%29%7D%20%5Cspace%5C%20and%20%5Cspace%5C%20the%20%5Cspace%5C%20e%5E%7Bln%2810x%29%7D)
can be simplified to
![2x \space\ and \space\ 10x](https://tex.z-dn.net/?f=2x%20%5Cspace%5C%20and%20%5Cspace%5C%2010x)
so we gots now
![2ln(2x)-ln(10x)=ln(30)](https://tex.z-dn.net/?f=2ln%282x%29-ln%2810x%29%3Dln%2830%29)
![ln((2x)^2)-ln(10x)=ln(30)](https://tex.z-dn.net/?f=ln%28%282x%29%5E2%29-ln%2810x%29%3Dln%2830%29)
![ln(4x^2)-ln(10x)=ln(30)](https://tex.z-dn.net/?f=ln%284x%5E2%29-ln%2810x%29%3Dln%2830%29)
![ln(\frac{4x^2}{10x})=ln(30)](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B4x%5E2%7D%7B10x%7D%29%3Dln%2830%29)
same base so
![\frac{4x^2}{10x}=30](https://tex.z-dn.net/?f=%5Cfrac%7B4x%5E2%7D%7B10x%7D%3D30)
![\frac{2x}{5}=30](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7B5%7D%3D30)
times both sides by 5
![2x=150](https://tex.z-dn.net/?f=2x%3D150)
divide both sides by 2
![x=75](https://tex.z-dn.net/?f=x%3D75)
answer is x=75