divide 6x^4+2x^3-6x^2-14x-1 by 3x+1 by using long divison show all work then explain if 3x+1 is a factor of the dividend
1 answer:
After working this problem out, we know that 3x + 1 is not a total factor of the dividend, because there is a remainder.
When you divide a polynomial by another polynomial, if there is a remainder, it is not a complete factor.
<h3><u>After dividing, we are left with: 2x^3 - 2x - 4 + (3/(3x + 1))</u></h3>There is a remainder of 3.
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<h2>The value of x = - 
</h2>
Step-by-step explanation:
The given expressiona are:
and
To find, the value of x = ?
∴
By crossmultiplication, we get
4(3x + 2) = 2(3x - 6)
⇒ 12x + 8 = 6x - 12
⇒ 12x - 6x = - 12 - 8
⇒ 6x = - 20
⇒ 3x = - 10
⇒ x = -
∴ The value of x = -
Thus, the value of x is equal to - .