8,9,10
how i found this out was if u replace m with 8 it will be 8+7 which is 15 and less then 18
for 9 its 9+7 which is 16 which is less then 18
and for 10 its 10+7 which is 17 which is less then 18
and for 11 its 11+7 is 18 which is equal to 18 so it would not apply to this equation
hope this helps
Answer:
36,960
Step-by-step explanation:
multiply 5280 by 7
Sea level would be 0
So if it is going -12 /ft/s then it is descending 12 feet per second
-120/-12 = 10
The correct answer would be 10 seconds
I hope this helps!
Answer:
3d + 4p = $37.25
5d + 2p = $38.75
Actual Answer:
Bag of popcorn is $5
A drink is $5.75
Step-by-step explanation:
Let drinks = d
Let popcorn = p
Noah: 3d + 4p = $37.25
Other: 5d + 2p = $38.75
Choose a variable to eliminate (We'll choose p)
3d + 4p = $37.25
(5d + 2p = $38.75) -2
Distribute
-10d - 4p = -77.5
The -4p cancels out the 4p, then we combine
-7d = -40.25
Divide both sides by -7
-7d/-7 = -40.25/-7
d = 5.75
Back to 3d + 4p = $37.25
Substitute d with 5.75
3(5.75) + 4p = $37.25
17.25 + 4p = 37.25
Move the constant to the other side
17.25 + 4p = 37.25
-17.25 -17.25
4p = 20
Divide both sides by 4
4p/4 = 20/4
p = 5
Answer:
The complete question in the graphic
A.
After synchronized exercise, it was observed that the average proximity rate has increased, which shows that the mean of the variable is positive and there is high synchronization in the groups.
.
B.
If groups with low synchronization and high effort are compared, the result of the average will be positive, so the average proximity rate will also increase after the synchronization exercise is performed.
On the contrary, if we observe the groups that have low synchronization and low effort, the mean of the variable is negative, thus the average proximity rate after performing the exercise will decrease.
(C)
considering that the total degrees of freedom is 259, it will show 260 students in the analysis.
D.
With a significance level of 5% or 0.05, the P value is less than the significance level, which leads to differentiating the mean of the scores before and after performing the combinations.
E.
With a significance level of 1% or 0.01, the p-value is higher than the significance level. With this data we can conclude that there is no difference between the results before and after the synchronized exercise