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Fantom [35]
3 years ago
10

Calculate the side lengths a and b to two decimal places.

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

D. <em>a</em> = 11.71 and <em>b</em> = 15.56

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Trigonometry</u>

  • All angles in a triangle add up to 180°

<u>Pre-Calculus</u>

  • Law of Sines: \frac{sin(A)}{a} =\frac{sin(B)}{b} =\frac{sin(C)}{c}

Step-by-step explanation:

<u>Step 1: Define</u>

AC = b

CB = a

AB = 7

m∠A = 45°

m∠B = 110°

m∠C = ?

<u>Step 2: Find missing ∠</u>

  1. Set up equation:                    m∠C + 45° + 110° = 180°
  2. Combine like terms:              m∠C + 115° = 180°
  3. Isolate unknown:                   m∠C = 25°

<u>Step 3: Find measure of </u><em><u>b</u></em>

  1. Substitute:                    \frac{sin(25)}{7} =\frac{sin(110)}{b}
  2. Cross-multiply:             bsin(25)=7sin(110)
  3. Isolate <em>b</em>:                       b=\frac{7sin(110)}{sin(25)}
  4. Evaluate:                       b=15.5645
  5. Round:                          b \approx 15.56

<u>Step 4: Find measure of </u><em><u>a</u></em>

  1. Substitute:                    \frac{sin(25)}{7} =\frac{sin(45)}{a}
  2. Cross-multiply:             asin(25)=7sin(45)
  3. Isolate <em>a</em>:                       a=\frac{7sin(45)}{sin(25)}
  4. Evaluate:                       a=11.7121
  5. Round:                          a \approx 11.71
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4 0
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Read 2 more answers
Determine the length and conductivity of a wire with diameter 4.2 mm constructed from an alloy of resistivity 3.2 x 10^-8 ohms-m
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Answer:

1) L = 3.465 × 10^2; 31250000 S/m

2) terminal pd = 11V

3) ₦2

Step-by-step explanation:

1)

diameter of wire (d) = 4.2mm = 4.2 × 10^-3m

resistivity 3.2 x 10^-8 ohms-meter

Resistance(R) = 0.8 ohms

Area of wire (A)= πd^2 / 4

A =[ ( 22/7) * (4.2×10^-3)^2] / 4

A = [22/7 * 17.64×10^-6] / 4

A = 13.86×10^-6m^2

Recall:

Resistivity = (R ×A) / Length

Length = (R × A) / resistivity

Length(L) = [(0.8)(13.86×10^-6)] / 3.2 x 10^-8

L = (11.088 × 10^-6) / 3.2 x 10^-8

L = 3.465 × 10^2

Conductivity = 1/resistivity

Conductivity = 1/3.2 x 10^-8

Conductivity = 31250000 S/m

2)

Series resistor = 1.5 and 4.0 ohms

e.m.f (E) = 12V, internal resistance 'r' = 0.5

Recall :

I = E / (R + r)

Where I = current

R = circuit resistance

R = Rs = 1.5 + 4.0 (series connection) = 5.5

Recall : I = V/R

Where V = voltage ( terminal pd)

Therefore,

V/R = E/(R+r)

V/5.5 = 12/(5.5 + 0.5)

V/5.5 = 12/6

V/5.5 = 2

V = 5.5 × 2

V = 11V

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Answer:

Step-by-step explanation:

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