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3 years ago

an ostrich can run at a rate of 50 miles in 60 minutes at this rate how long would it take an ostrich to run 15 miles

Mathematics

1 answer:

vova2212 [387]3 years ago

5 0

This is direct proportion - it takes less time to run 15 miles than 50 miles. Show the comparison:

5060=15x

50x=60×15

x=60×1550

x=18minutes

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makvit [3.9K]

Answer:

Step-by-step explanation:

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Answer:

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pentagon [3]

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Read 2 more answers

Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and the sample size.

pentagon [3]

Answer:

$\bar X= \mu = 25$

$\sigma_{\bar X}= \frac{7}{\sqrt{15}}= 1.807$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the following conditions

Where $\mu=25$ and $\sigma=7$

And for this case we select a sample size of n= 15. and we want to know the distribution for the sample mean $\bar X$ . We can assume that the distribution for $\bar X$ is approximately normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Asuming that the distribution for X is also approximately normal. So then the parameters are:

$\bar X= \mu = 25$

$\sigma_{\bar X}= \frac{7}{\sqrt{15}}= 1.807$

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3 years ago