Assuming the order doesn't matter it would be 10c6 = 210 ways
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:


In the figure, the slope of mid-segment DE is -0.4. The slope of segment AC is?
A.) 0.4
B.) -0.4
C.) 2
D.) -2

Step-by-step explanation:

# i hope it helps you
# mark me brainliest thank you
Answer:
$270
Step-by-step explanation:
Multiply 1000 by .03 or 3%. Then mulrioly that number by 9 because it is that amoint of interest for nine months.
Answer:
idk either sorry but
Step-by-step explanation:
I think you need a protractor to help you find the other angles to find x