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lisabon 2012 [21]
4 years ago
5

Total sales: $3546.95

Mathematics
1 answer:
Snezhnost [94]4 years ago
5 0

Answer:

commission 446.9157$ or 446.92 $ and total pay 1646.92 $

Step-by-step explanation:

commission = 12.6% of 3546.95

                    = (12.6/100)×3546.95    

                    =  $446.9157

total pay = basic pay + commission

               = 1200+446.92

               = 1646.92 $

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Find the volume of a pyramid with a square base, where the side length of the base is 10.9 m and the height of the pyramid is 4.
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Answer:

V=186.1\ m^3

Step-by-step explanation:

<u>Volume of a Pyramid</u>

The volume of a pyramid with base area Ab and height H is given by:

\displaystyle V=\frac{A_b*H}{3}

If the base is a square of side length L, then its area is:

A_b=L^2

Thus, substituting the above equation in the first:

\displaystyle V=\frac{L^2*H}{3}

The side length is L=10.9 m and the height is 4.7 m, thus the volume is:

\displaystyle V=\frac{10.9^2*4.7}{3}

\displaystyle V=\frac{558.407}{3}

\boxed{V=186.1\ m^3}

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Sara had 51 stickers and her dad had 13 stickers how many are in all
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64

Step-by-step explanation:

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Darlene wrote this proof of the identity (x+y)^2-(x-y)^2=4xy. Which of the following is a justification for step 5 for her proof
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A plane flying horizontally at an altitude of 1 mi and a speed of 470 mi/h passes directly over a radar station. Find the rate a
kiruha [24]

Answer:

407 mi/h

Step-by-step explanation:

Given:

Speed of plane (s) = 470 mi/h

Height of plane above radar station (h) = 1 mi

Let the distance of plane from station be 'D' at any time 't' and let 'x' be the horizontal distance traveled in time 't' by the plane.

Consider a right angled triangle representing the above scenario.

We can see that, the height 'h' remains fixed as the plane is flying horizontally.

Speed of the plane is nothing but the rate of change of horizontal distance of plane. So, s=\frac{dx}{dt}=470\ mi/h

Now, applying Pythagoras theorem to the triangle, we have:

D^2=h^2+x^2\\\\D^2=1+x^2

Differentiating with respect to time 't', we get:

2D\frac{dD}{dt}=0+2x\frac{dx}{dt}\\\\\frac{dD}{dt}=\frac{x}{D}(s)

Now, when the plane is 2 miles away from radar station, then D = 2 mi

Also, the horizontal distance traveled can be calculated using the value of 'D' in equation (1). This gives,

2^2=1+x^2\\\\x^2=4-1\\\\x=\sqrt3=1.732\ mi

Now, plug in all the given values and solve for \frac{dD}{dt}. This gives,

\frac{dD}{dt}=\frac{1.732\times 470}{2}=407.02\approx 407\ mi/h

Therefore, the distance from the plane to the station is increasing at a rate of 407 mi/h.

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4 years ago
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