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LUCKY_DIMON [66]
3 years ago
6

Prove that the value of the expression: (125^2+25^2)(5^2–1) is divisible by 39

Mathematics
1 answer:
prisoha [69]3 years ago
4 0

Answer:

(1252+252)(52−1)

=(1252+252)(52+−1)

=(1252)(52)+(1252)(−1)+(252)(52)+(252)(−1)

=390625−15625+15625−625

=390000

divide by 39 is

=10000

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Answer:

the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis

4 0
3 years ago
Using proportional reasoning, about how many of 180 seventh grade students in school would like to snorkel
amm1812

Answer:

We need some aditional data. For example, the average number of students who like to snorkel in certain population.

Step-by-step explanation:

3 0
3 years ago
The product of 8 and x plus the quotient of y and 7. answer choices are (8 + x)/(7 + y) (8x) + (y/7) (8 + x)(y/7)
Cerrena [4.2K]

Answer: (8x) + (y/7)

The word 'product' means multiplication and the word 'quotient' means division. Only (8x) + (y/7) multiplies 8 and x while diving y and 7.

3 0
3 years ago
NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400
Ne4ueva [31]

Answer:

The test statistics is  t  =  -1.727

Step-by-step explanation:

From the question we are told that

The data given is  

   330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

 The population mean is  \mu  =  14400

    The  sample  size is  n =  16

  The  null hypothesis is  \mu \le  14400

    The  alternative hypothesis is  H_a  :  \mu > 14400

The sample mean is mathematically evaluated as

  \= x  =  \frac{\sum x_i}{n}

So

   \= x  =  \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}

=>  \= x = 10799.9

The  standard deviation is mathematically represented as

      \sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}

So

\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}}  \ ..

   ..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2  }{16}} \ ...

  \ ... \sqrt{\frac{(23812 - 10799.9)^2 +(25814 - 10799.9)^2 }{16}}

=>  \sigma  =  8340

  Generally the test statistic is mathematically represented as

  t =  \frac{10799.9- 14400}{ \frac{8340}{\sqrt{16} } }

t  =  -1.727

From the z-table  the p-value is  

     p-value  = P(Z > t) =  P(Z >  -1.727) =  0.95792

 From the values obtained we see that

        p-value  >  \alpha  so we fail to reject the null hypothesis

Which implies that the claim of the NarStor is wrong

5 0
3 years ago
larry ran 220 meters farther that leigh ran. leigh ran 2.3 kilometers. how many kilometers did larry run?
Gala2k [10]
Larry ran 2.52 killometers. Since a meter is 0.001 killometers, you have to do 0.001 x 220 which is 0.22 then do 2.3 + 0.22 and get 2.52.
6 0
3 years ago
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