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Anestetic [448]
3 years ago
9

X÷0.4=2 1/9 ÷3 1/6 solve for x

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Answer:

x = 0.27

Step-by-step explanation:

Given:

x÷0.4=2 1/9 ÷3 1/6

To Find:

x = ?

Solution:

First we will see what is

2\frac{1}{9}= \frac{2\times 9 + 1}{9} \\\\2\frac{1}{9}= \frac{18 + 1}{9} \\\\2\frac{1}{9}= \frac{19}{9} \\\\Similarly,\\\\3\frac{1}{6}= \frac{3\times 6 + 1}{6} \\\\3\frac{1}{6}= \frac{18 + 1}{6} \\\\3\frac{1}{6}= \frac{19}{6} \\

Now the final equation is

\frac{x}{0.4} =\frac{\frac{19}{9}}{\frac{19}{6}}\\\\\frac{x}{0.4} =\frac{6}{9}\\\\\frac{x}{0.4} =\frac{2}{3}\\\\\therefore x = 0.4\times \frac{2}{3}\\\\x = \frac{0.8}{3}\\\\x=0.2666\\\\x=0.27

x = 0.27

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One light-year equals 5.9 x 1012 miles. How many light-years are in 6.79
inna [77]

Option B

The number of light years in 6.79 \times 10^{16} miles is 11508 light years

<em><u>Solution:</u></em>

Given that,

One light-year equals 5.9 x 10^12 miles

Therefore,

1 \text{ light year } = 5.9 \times 10^{12} \text{ miles }

To find: Number of light years in 6.79 \times 10^{16} miles

Let "x" be the number of light years in 6.79 \times 10^{16} miles

Then number of light years in 6.79 \times 10^{16} miles can be found by dividing 6.79 \times 10^{16} miles by miles in 1 light year

\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79 \times 10^{16}}{5.9 \times 10^{12}}\\\\\text{Use the law of exponent }\\\\\frac{a^m}{a^n} = a^{m-n}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79}{5.9} \times 10^{16-12}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 1.1508 \times 10^4\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 11508

Thus number of light years in 6.79 \times 10^{16} miles is 11508 light years

3 0
3 years ago
Please please please please help i need to pass please
labwork [276]

Answer:

D

Step-by-step explanation:

Solution:-

The standard sinusoidal waveform defined over the domain [ 0 , 2π ] is given as:

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Where,

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                 k: The phase difference

                 b: The vertical shift of center line from origin

We are given that the function completes 2 cycles over the domain of [ 0 , 2π ]. The number of cycles of a sinusoidal wave is given by the frequency parameter ( w ).

We will plug in w = 2. No information is given regarding the phase difference ( k ) and the position of waveform from the origin. So we can set these parameters to zero. k = b = 0.

The resulting sinusoidal waveform can be expressed as:

                           f ( x ) = sin ( 2x )  ... Answer

4 0
3 years ago
A lighthouse keeper has a 10 degrees angle of depression between the horizontal light beam and the line of sight from the ship.
Andrei [34K]
107.75m
This is a trigonometric ratio problem. the angle of depression (10) is opposite the height (19m) and the distance is adjacent to the distance (x). opposite ad adjacent sides to the angle is a tangent problem.
tan \theta = \frac{opp}{adj}
plus in values, we know.
tan (10) = \frac{19}{x}
switch tan(10) and x using the products property.
x = \frac{19}{tan (10)}
plug in to calulator to get answer
x=107.75

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Answer:

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Step-by-step explanation:

3 0
3 years ago
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