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stiks02 [169]
3 years ago
11

Which describes the solution set of (5x –1)(x + 2) = 8x – 4?

Mathematics
1 answer:
Lana71 [14]3 years ago
5 0
(5x-1)(x+2)=8x-4
5x²+10x-x-2=8x-4
5x²+9x-2=8x-4
5x²+x+2=0
use the quadratic formula, b²-4ac=1²-4*5*2=1-40=-39, -39 cannot be square rooted, so the equation has no real solution. 
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DaniilM [7]
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We collect the terms:
8n^2 -10n + 137 = 0

The steps for completing the square:

1) Move the "non X" (or "non N") term to the right:

8n^2 -10n  = -137

<span>2)<span> Divide the equation by the coefficient of N² which in this case is 8
n^2 -1.2n = </span></span><span><span>-17.125 </span>

3) Take the coefficient of "N"; divide it by 2; square it; add it to both sides of the equation.
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</span>
n^2 -1.2n +.36 = <span>-17.125 +.36

Take the square root of both sides:</span>
(n-.6)*(n-.6) = sq root( <span> <span> <span> -16.765 </span> </span> </span> )
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3 years ago
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Answer:

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