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3 years ago

Which describes the solution set of (5x –1)(x + 2) = 8x – 4?

1 answer:

5 0

(5x-1)(x+2)=8x-4
5x²+10x-x-2=8x-4
5x²+9x-2=8x-4
5x²+x+2=0
use the quadratic formula, b²-4ac=1²-4*5*2=1-40=-39, -39 cannot be square rooted, so the equation has no real solution.

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For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

Not school work. y’all i need to know something.

LUCKY_DIMON [66]

Ask your teachers if you can still turn them in

4 0

2 years ago

Read 2 more answers

How do i solve for x

GarryVolchara [31]

Answer:

X is 36 and y is 48.

Step-by-step explanation:

So a couple of things here: both triangles are equal, and triangles always add up to 180 degrees. If we do some math:

180-108-48=24

This means that 2x-y needs to equal 24. We know what y is, it's 48 since both triangles are equal. Lets do some more math to find x.

48+24=72

72 divided by 2 = 36. 36 is the answer for x.

7 0

2 years ago

Student grades on a chemistry exam were: 77, 78, 76, 81, 86, 51, 79, 82, 84, 99

IrinaK [193]

Answer:

Step-by-step explanation:

A) Stem-and-leaf plot

stem leaf

5 1

7 6,7,8,9

8 1,2,4,6

9 9

B) Outlier

Could consider 51 an outlier.

3 0

2 years ago

Gabriella made 36 cookies. She gave away 28 cookies. Use the equation 28 + c = 36 to find c, the number of cookies she kept.

Lera25 [3.4K]

c=8

Hope it helps Hve a nice day

6 0

2 years ago

Read 2 more answers