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stiks02 [169]
3 years ago
11

Which describes the solution set of (5x –1)(x + 2) = 8x – 4?

Mathematics
1 answer:
Lana71 [14]3 years ago
5 0
(5x-1)(x+2)=8x-4
5x²+10x-x-2=8x-4
5x²+9x-2=8x-4
5x²+x+2=0
use the quadratic formula, b²-4ac=1²-4*5*2=1-40=-39, -39 cannot be square rooted, so the equation has no real solution. 
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When the transmogrifiers are made at the factory, they move along a conveyer belt. Every 8th transmogrifier gets a blue control
MaRussiya [10]

Answer:

  • Blue - 18, green - 50, with photo - 37

Step-by-step explanation:

<u>Total number = 150</u>

  • Blue = 150/8 = 18 (integer part)
  • Green = 150/3 = 50
  • Spaceman Spiff autograph = 150/4 = 37 (integer part)
4 0
2 years ago
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Solve the riddle i am 6 more than 2 times 9 what number am i now make up your own riddle for the number 68
Lesechka [4]

The riddle answer is 24.

A riddle for the number 68 is: 12 more than 14 times 4


5 0
2 years ago
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A delivery truck made 8 stops in one neighborhood. By stop 5, there were 11 packages delivered. This graph shows this informatio
IceJOKER [234]
2 delivery stops

Find the point that hits 5 on the "packaging delivery".

Then look down to find the 'x'

your x is 2

hope this helps
6 0
3 years ago
Expand and simplify (2x+5y) (x-3y)
Dmitry [639]
Should be simple:

Let's take this one at a time.

2x(x-3y)

You'd get:
2x^2-3xy
for the first one.

2nd one:
5y(x-3y)
you'd get:
+5xy-3y^2

Put them both together:
2x^2-3xy+5xy-3y^2

Combine like terms.

Your Answer:
2x^2+2xy-3y^2

3 0
2 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
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