Question

What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)?

Answer 1

Answer:

$-2x+5$

Step-by-step explanation:

The given equation is:

$\frac{125-8x^3}{25+10x+4x^2}$

On dividing and simplifying the above equation, we get

=$\frac{-(2x-5)(4x^2+10x+25)}{4x^2+10x+25}$

Solving the like terms, we get

=$-(2x-5)$

=$-2x+5$

which is the required quotient of the given equation.

Answer 2

Your answer is:
(125 - 8x^3) / (25 + 10x + 4x^2) = - ((2x - 5) * (4x^2 + 10x + 25)) / (4x^2 + 10x + 25) = - (2x - 5) = - 2x + 5

The correct result would be - 2x + 5.