What is the quotient (125 – 8x3) ÷ (25 + 10x + 4x2)?

Mathematics

2 answers:

otez555 [7]2 years ago

8 0

Answer:

$-2x+5$

Step-by-step explanation:

The given equation is:

$\frac{125-8x^3}{25+10x+4x^2}$

On dividing and simplifying the above equation, we get

= $\frac{-(2x-5)(4x^2+10x+25)}{4x^2+10x+25}$

Solving the like terms, we get

= $-(2x-5)$

= $-2x+5$

which is the required quotient of the given equation.

ahrayia [7]2 years ago

6 0

Your answer is:
(125 - 8x^3) / (25 + 10x + 4x^2) = - ((2x - 5) * (4x^2 + 10x + 25)) / (4x^2 + 10x + 25) = - (2x - 5) = - 2x + 5

The correct result would be - 2x + 5.

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