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2 years ago

Please help me!! im so close to finshing

Mathematics

1 answer:

gtnhenbr [62]2 years ago

8 0

Answer:

do you want me to answer this too

Step-by-step explanation:

???

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Suppose that in 6 minutes, 36 gallons of water came out the pipe. what was the rate in

Tom [10]

Answer:

6 gallons in one minute :)

Step-by-step explanation:

3 0

3 years ago

Help ASAp peaseeeeeeeeee

PIT_PIT [208]

Answer:

7/6

Step-by-step explanation:

$\frac{ \frac{x}{4} + \frac{x}{3} }{ \frac{x}{2} } = \frac{x( \frac{1}{4} + \frac{1}{3} )}{ x(\frac{1}{2}) } \\ = \frac{ \frac{1}{4} + \frac{1}{3} }{ \frac{1}{2} } \\ = \frac{14}{12} = \frac{7}{6}$

3 0

2 years ago

Read 2 more answers

A student receives test scores of 62, 83, and 91. This student's term project score is 88. Each test is worth 20% of the final g

miskamm [114]

Answer:

The student's current average score will be 69.2

Step-by-step explanation:

Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

Let third test be TEST C: which is 20 of total and has secured 91.

And now the TEST D which is 25 of total and has secured 88.

Therefore, by multipying across

${0.2}\times{62}$ = 12.4

${0.2}\times{83}$ = 16.6

${0.2}\times{91}$ = 18.2

${0.25}\times{88}$ =22

Now, by adding the scores to get the average score

We get, 69.2.

6 0

3 years ago

Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F

Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

3 0

3 years ago

What is a equivalent fraction for 4/21

joja [24]

One equivalent fraction for 4/21 could be 8/42.

3 0

3 years ago