Question

PLEASE HELP To prove that ΔAED ˜ ΔACB by SAS, Jose shows that

Answer 1

Answer:

Jose also has to state that

∠ A ≅∠ A ...............{Reflexive Property}

Step-by-step explanation:

Given:

Jose Shows

$\frac{AE}{AC}= \frac{AD}{AB}$

TO Prove :

Δ AED ~ Δ ACB  by SAS postulate.

Proof:

Jose also has to state that

∠ A ≅∠ A ...............{Reflexive Property}

In  Δ AED and Δ ACB  

$\frac{AE}{AC}= \frac{AD}{AB}$     ……….{Given}

∠ A ≅ ∠ A    …………..{Reflexive Property}

Δ AED ~ Δ ACB ….{ By Side-Angle-Side test}

Answer 2

Answer:

first option

Step-by-step explanation:

∠ A ≅∠ A