Y=mx+c is the slope standard form
5y=-30-4x
5y=-4x-30
Y=-4/5x-6
Answer:

Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
(3*j)-8
I thinkkkk... I’m positive tho
Answer:
y = 3/4x + 4
Step-by-step explanation:
to put it into slope intercept form, you need to find the y intercept or b becasue the slope intercept form is y = mx + b where b is the y intercetpt and m is the slope. To find b you insert the points you were given so 1 = -4(3/4) + b
which simplifies to 4 = b so then you can put in your slope and y intercept into slope intercept form