To solve for this, set up a proportion.
21/40 = x/100.
Cross multiply the fraction's numerators with the denominators;
21 x 100, 40 and x.
2100/40x.
Divide both numbers by 40 to get x.
2100/40 = 52.5
21 is 52.5% of 40.
I hope this helps!

5 0

3 years ago

Adult tickets to space amusement parkcost x dollars. Children's tickets cost y dollars. The henson family bought 3 aduly and 1 c

vesna_86 [32]

Answer:

3x + 1y = $163

2x + 3y =$174

Step-by-step explanation:

Adult tickets to space amusement park cost x dollars children’s tickets cost y dollars.

Henson family bought 3 adults and 1 child's tickets for $163

x + y = 163

3x + 1y = 163

The Garcia family bought 2 adults and 3 child’s ticket for $174.

x + y = $174

2x + 3y = $174

Therefore the equations representing both families cost are

Henson family

3x + 1y = $163

Garcia family

2x + 3y = $174

3 0

3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

-------------------------------------------------------------

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

It's 90

6 0

3 years ago

A smoothie recipe calls for 13 cup yogurt for each smoothie. How many cups of yogurt are needed to make 7 smoothies?

Sauron [17]

You could also say.
13 x
--- = ---
1 7
Multiply across.
1x=13×7
1x =91
Divide both sides by one.
x=91.
91 cups of yoygurt are needed to make 7 Smoothies.
Or you could do it the easy way.
whatever makes you happy. :)

3 0

3 years ago

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