3 years ago

What is the square root of -1?

Mathematics

2 answers:

sladkih [1.3K]3 years ago

5 0

The answer to your problem is----> i

solmaris [256]3 years ago

3 0

$\sqrt{-1} = i$

However, in Real Number System, you can't find the value of square root of negative numbers. The above one is the imaginary number.

You might be interested in

Factor x 2 + xy - 2x - 2y.

steposvetlana [31]

Factor by groupins
x^2 + xy - 2x - 2y

= x(x + y) - 2(x + y)

= (x - 2(x + y)

4 0

3 years ago

Read 2 more answers

Which of these is not an economic activity?

fiasKO [112]

Answer:

D. helping a friend decorate for s party

8 0

3 years ago

Read 2 more answers

Frações Algébricas - 3* caso <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B1%7D%7B2x-4%7D%20%20%2B%20%5Cfrac%7Bx-1%7D%7B3x-6%7

Ulleksa [173]

Answer:

$\dfrac{5x + 1}{6(x - 2)}$

$\dfrac{5x + 1}{6x - 12}$

Step-by-step explanation:

Fatorizam-se os denominadores.

2x - 4 = 2(x - 2)

3x - 6 = 3(x - 2)

O minimo multiplo comum dos denominadores e

2(3)(x - 2)

$\dfrac{x + 1}{2x - 4} + \dfrac{x - 1}{3x - 6} =$

$= \dfrac{3(x + 1)}{2(3)(x - 2)} + \dfrac{2(x - 1)}{2(3)(x - 2)}$

$= \dfrac{3(x + 1) + 2(x - 1)}{6(x - 2)}$

$= \dfrac{3x + 3 + 2x - 2)}{6(x - 2)}$

$= \dfrac{5x + 1}{6(x - 2)}$

$= \dfrac{5x + 1}{6x - 12}$

4 0

3 years ago

"Question": Expand (2x-3y)^3<br><br> Real question: Why am I not ace rank yet?

Hitman42 [59]

Answer: (6x-3y)3 or maybe not possible to do

Step-by-step explanation

multiply 3x2 and get 6. Multiply 3x3 and get 9.

5 0

3 years ago

Read 2 more answers

Write the answer in simplest form: 5/6 − 3/5 I need this ASAP pls help

RSB [31]

Answer:

the answer is 7/30 (answer is .23 repeating)

3 0

3 years ago